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Pavel [41]
3 years ago
13

If y varies directly with x, and y = 2 when x = −4, what is the value of y when x = 20 ?

Mathematics
2 answers:
balu736 [363]3 years ago
8 0

Answer:

y=kx

2=k.-4

k=-1/2

then

y=-1/2×20

y=-10

ASHA 777 [7]3 years ago
6 0

Answer:

y = - 10

Step-by-step explanation:

Given that y varies directly with x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 2 when x = - 4, that is

2 = - 4k ( divide both sides by - 4 )

\frac{2}{-4} = k, that is

k = - \frac{1}{2}

y = - \frac{1}{2} x ← equation of variation

When x = 20, then

y = - \frac{1}{2} × 20 = - 10

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2/5;0.5 tell whether each pair shows equivalent number
Georgia [21]
2/5= 40%, so no, they are not equivalent numbers,<span />
4 0
3 years ago
A bag contains 50 lottery balls, numbered 1-50. A ball is chosen at random, then a month of the year is selected. What is the pr
Morgarella [4.7K]

Answer:

4/75

Step-by-step explanation:

We have two sample spaces

1.Lottery balls

2. Month of the year

For lottery balls the sample space is S= 50

Multiples of 3 between 1 and 50 are

(3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48)= 16 in numbers

Hence the probability of choosing a multiple of 3

Pr(multiple of 3) = 16/50= 8/25

Also the sample space for months of the year is S= 12

Two months starts with letter m, March and may

Pr(of months with m) = 2/12= 1/6

the probability of choosing a multiple of 3 and a month starting with the letter M= 8/25*1/6= 8/150= 4/75

6 0
4 years ago
Y=2(x+1)^2 has how many real roots
oee [108]

The equation y= 2(x+1)^2 has one real root and that is x=-1.

What is real roots of the equation?

    We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation X^2-7x+12=0 is solved, the actual roots are 3 and 4.

Here given,

=> y = 2(x+1)^2

Take y=0 then,

=> 2(x+1)^2=0

=> (x+1)^2=0

=>(x+1)=0

=> x=-1

Hence the given equation has one real root and that is x=-1.

To learn more about real roots refer the below link

brainly.com/question/24147137

#SPJ1

8 0
1 year ago
Read 2 more answers
Hey smart math people help me please
Ymorist [56]

Answer: First off thats not how you ask for help, by calling us "smart math people" that could offend someone...Second off the answer is 10 because

Step-by-step explanation:

A^2 + B^2 = C^2

6^2 + 8^2 = C^2

36 + 64 = 100 square root that = 10

Answer: 10

3 0
3 years ago
Read 2 more answers
Got It? Do these problemst
dedylja [7]
I did where you subtract 4 from both sides then divide 2 from 4 and you get 0.5 as x for your answer but im not sure
6 0
3 years ago
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