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3 years ago

5

:o does anyone else have a great dane that is as tall as u when shes on her back legs and shes not fully grown...bc i do and im

kinda mad about it

2 answers:

AleksAgata [21]3 years ago

7 0

Answer:

Sadly yes TnT. Well mines a boy and I think he knows I hate it.

Explanation:

frez [133]3 years ago

5 0

no I don’t . I do not thanks

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A cannon is fired from a castle wall at some unknown height above the ground. The cannonball leaves the cannon with speed 30.0m/

Sauron [17]

Answer:

Part a)

$t = 3.85 s$

Part b)

$h = 72.67 m$

Part C)

$v_x = 25.98 m/s$

$v_y = 0$

Part d)

In horizontal direction velocity will remain constant

$v_x = 30 cos30 = 25.98 m/s$

in vertical direction we have

$v_y = -22.77 m/s$

Explanation:

Part a)

Horizontal speed of the cannon

$v = 30.0 m/s$

angle of projection

$\theta = 30^o$

now we have

horizontal speed = $v_x = vcos30 = 30 cos30 =25.98 m/s$

vertical speed = $v_y = vsin30 = 30 sin30 = 15 m/s$

now the time taken by it to cover the distance 100 m from the wall

$x = v_x t$

$100 = 25.98 t$

$t = 3.85 s$

Part b)

Since it hits the ground in the same time

so the height of the castle is given as

$h = \frac{1}{2}gt^2$

$h = \frac{1}{2}(9.81)(3.85^2)$

$h = 72.67 m$

Part C)

At highest point of the projection

the vertical component of the velocity will become zero

so we will have

$v_x = 25.98 m/s$

$v_y = 0$

Part d)

In horizontal direction velocity will remain constant

so we have

$v_x = 30 cos30 = 25.98 m/s$

in vertical direction we have

$v_y = v_i + at$

$v_y = 15 - 9.81(3.85)$

$v_y = -22.77 m/s$

Part e)

8 0

3 years ago

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A force of 16.88 n is applied tangentially to a wheel of radius 0.340 m and causes an angular acceleration of 1.20 rad/s2. What

telo118 [61]

Answer:

4.78 kg/m^2.

Explanation:

τ = Iα

Where,

τ = torque, around a defined axis (N∙m)

I = moment of inertia (kg∙m2)

α = angular acceleration

= 1.2 rad/s^2

τ = F * r

= 16.88 * 0.34

= 5.74 N.m

Therefore, I = 5.74/1.2

= 4.78 kg/m2

6 0

3 years ago

A roller coaster is at the top of a 102 m hill and a mass of 120 kg. The coaster (at this

dybincka [34]

Height=h=102m
Mass=m=120g
Acceleration due to gravity=g=10m/s^2

$\\ \sf\longmapsto P.E=mgh$

P E means potential energy

$\\ \sf\longmapsto P.E=102(120)(10)$

$\\ \sf\longmapsto P.E=122400J$

7 0

3 years ago

At what pressure will the mean free path in room-temperature (20?c) nitrogen be 1.5 m ?

kondaur [170]

In physical chemistry, the mean free path is the average distance between the atoms during collision. Its formula is

$Mean \ free \ path \ = \frac{RT}{ \sqrt{2} \pi d^{2} N_{A}P }$

where d is the diameter of the Nitrogen atom (d = 310 x 10^-7 m), Na is Avogadro's number (Na=6.022 x 10^23), R is the gas constant (8.314 J/mol-K), T is the absolute temperature (T= 20 + 273 = 293 K). Substituting the values,

$1.5 = \frac{(8.314)(293)}{ \sqrt{2} \pi (310 \ x\ 10^{-7} )^{2} (6.022 \ x\ 10^{23} )P }$
P = 6.32 x 10^-13 Pascals

6 0

4 years ago

A satellite orbiting above the earth needs no power source to keep orbiting the earth.

abruzzese [7]

Answer:

True

Explanation:

The earths gravitational pull keeps it consistent with its orbit.

8 0

3 years ago

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