An object of mass 8 kg Is attached to a massless string of length 2 m And Suong With a tangentialVelocity of 3 m/s what isThe te
1 answer:
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Answer:
<em>(a) The average velocity is 16 m/s</em>
<em>(b) The acceleration is 0.4 m/s^2</em>
<em>(c) The final velocity is 24 m/s</em>
Explanation:
<u>Constant Acceleration Motion</u>
It's a type of motion in which the velocity (or the speed) of an object changes by an equal amount in every equal period of time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, final speed is calculated as follows:
The distance traveled by the object is given by:
(a) The average velocity is defined as the total distance traveled divided by the time taken to travel that distance.
We know the distance is x=640 m and the time taken t= 40 s, thus:
The average velocity is 16 m/s
Using the equation [1] we can solve for a:
(c) From [2] we can solve for a:
Since vo=8 m/s, x=640 m, t=40 s:
The acceleration is 0.4 m/s^2
(b) The final velocity is calculated by [1]:
The final velocity is 24 m/s