The name of the group of science that deals with earth and its neighbors in space is called

Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving -1.72 m/s. What is the veloc

Nuetrik [128]

The velocity of B after elastic collision is 3.45m/s

This type of collision is an elastic collision and we can use a formula to solve this problem.

<h3>Elastic Collision</h3>

$v_2 = \frac{2m_1u_1}{m_1+m_2} - \frac{m_1 - m_2}{m_1 + m_2}u_2$

The data given are;

m1 = 281kg
u1 = 2.82m/s
m2 = 209kg
u2 = -1.72m/s
v1 = ?

Let's substitute the values into the equation.

$v_1 = \frac{2*281*2.82}{281+209} -\frac{281-209}{281+209}(-1.72)\\v_1 = 3.45m/s$

From the calculation above, the final velocity of the car B after elastic collision is 3.45m/s.

Learn more about elastic collision here;

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4 0

2 years ago

A centrifuge in a forensics laboratory rotates at an angular speed of 3,700 rev/min. When switched off, it rotates 46.0 times be

ra1l [238]

Answer:

Explanation:

Given,

initial angular speed, ω = 3,700 rev/min

= $3700\times \dfrac{2\pi}{60}=387.27\ rad/s$

final angular speed = 0 rad/s

Number of time it rotates= 46 times

angular displacement, θ = 2π x 46 = 92 π

Angular acceleration

$\alpha = \dfrac{\omega_f^2 - \omega^2}{2\theta}$

$\alpha = \dfrac{0 - 387.27^2}{2\times 92\ pi}$

$\alpha = -259.28 rad/s^2$

3 0

3 years ago

A charged particle enters into a uniform magnetic field such that its velocity vector is perpendicular to the magnetic field vec

Phoenix [80]

Answer:

The particle path will follow

(d) a circular path

Explanation:

When a charged particle having charge of magnitude ' $q$ ' enters into a magnetic field such that its velocity vector ' $\vec{V}$ ' is perpendicular to the direction of the magnetic field ' $\vec{B}$ ', then it will experience a force, called Lorentz force ( $\vec{F_{L}}$ ), given by

$\vec{F_{L}} = \vec{V} \times \vec{B}$

As shown in the figure, the magnetic field is directed perpendicular to the plane and towards the plane (as shown by the circle and 'X'-sign) and the velocity vector is from left to right on the plane.

According to the property of cross-product, the Lorentz force ( $F_{L}$ ) acting on the particle will be perpendicular to the instantaneous position of the particle, making the path of the particle to be a circular path,as shown in the figure.

7 0

3 years ago

A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s,

Serhud [2]

By using the equation speed = distance/time we can solve for distance. The speed is 4 m/s and the time is 12 seconds. We need to rearrange the equation to Speed * Time = distance. 4(12) = 48; 48 = distance. The cliff is 48 meters high.

3 0

2 years ago

If Joe rides his bike for 15 minutes at 20 km/hour south, how far has he ridden? (Give the answer in km) Watch the units!

Virty [35]

Answer:

Distance covered by Joe, d = 5 km

Explanation:

It is given that,

Speed of Joe, v = 20 km/hour

Time taken by Joe, t = 15 minutes = 0.25 h

We need to find the distance he is covering. It can be calculated using definition of speed as :

$v=\dfrac{d}{t}$