We write the equation in terms of dy/dx,
<span>y'(x)=sqrt (2y(x)+18)</span>
dy/dx = sqrt(2y + 18)
dy/dx = sqrt(2) ( sqrt(y + 9))
Separating the variables in the equation, we will have:
<span>1/sqrt(y + 9) dy= sqrt(2) dx </span>
Integrating both sides, we will obtain
<span>2sqrt(y+9) = x(sqrt(2)) + c </span>
<span>where c is a constant and can be determined by using the boundary condition given </span>
<span>y(5)=9 : x = 5, y = 9
</span><span>sqrt(9+9) = 5/sqrt(2) + C </span>
<span>C = sqrt(18) - 5/sqrt(2) = sqrt(2) / 2</span>
Substituting to the original equation,
sqrt(y+9) = x/sqrt(2) + sqrt(2) / 2
<span>sqrt(y+9) = (2x + 2) / 2sqrt(2)
</span>
Squaring both sides, we will obtain,
<span>y + 9 = ((2x+2)^2) / 8</span>
y = ((2x+2)^2) / 8 - 9
Answer:201 students
Step-by-step explanation: Since there are seven kids riding in cars, you would subtract 7 from 1213 to get 1206 students. The six buses means you divide by 6 to get 201 students in each bus.
D) (10 x 55) + (10 x 55) + (10 x 55) + (10 x 55)
use distributive rule to factor out 55:
55 (10+10+10+10) = 55×40
Answer: -3, -1, 0, 2, |4|, |-8|
The absolute values would be positive, which would lead to them being after the 0.
Average = mean = sum of the values / number of data
Values = h, j, and k
Number of data = 3
Sum of the values = h + j + k
Mean = [h + j + k] / 3
=> Answer: option c. [h+j+k] over 3
