Answer:
-1
Step-by-step explanation:
i= -1^(1/2)
= -1^(1/2 x 34)
= -1^(17)
= -1
=2(5x2+20x-1)
The 2 by the x has to be on top of the x
For number 25 it’s x=4 and for 26 it’s x=7
Answer:
We need a sample of size at least 13.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

90% confidence interval: (0.438, 0.642).
The proportion estimate is the halfway point of these two bounds. So

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Using the information above, what size sample would be necessary if we wanted to estimate the true proportion to within ±0.08 using 95% confidence?
We need a sample of size at least n.
n is found when M = 0.08. So






Rounding up
We need a sample of size at least 13.