When soap is added then the paper clip will fall as soap is a surfactant and decreases the surface pressure. The surface strain of water holds the paper.
<h3>What is the mechanism of floatation?</h3>
The paper clip is lighter in weight and floats on the water surface as the density and mass play a major role in floatation. Any addition of substances like soap will lead the clip to fall or sink.
The addition of the soap lessens the pressure of the water surface as it is a surfactant and will affect the surface strain of water.
Therefore, when soap is added, paper clips will fall.
Learn more about surfactants here:
brainly.com/question/11752340
Answer:
17.27 atm
Explanation:
Use the ideal gas law or PV = nRT
We are solving for pressure here so lets isolate for P before we plug in values:
So first to get n or the number of moles we need to convert the grams of N2O to moles of N2O. We can do this by multiplying by the inverse of the molar mass like so:
Our grams of N2O would cancel and give us 11.813 mol of N2O
Now all thats left is to plug in and solve with the correct value for R which in this case for all of our units to cancel is 0.08206
P = 17.27 atm
(I would double check the calculator work if it is for correctness just be sure)
To illustrate the Lewis structure,
P has 5 valence electrons
O has 6 valence electrons (each for 4 oxygen)
And finally, for every negative charge, there is an additional valence electron
We should add these all up = 5 + 24 + 3 = 32 valence electrons
With this, we can be guided to illustrate the lewis structure as P as central atom and the 3 oxygen each with a single bond with P and 1 oxygen with a double bond with P. We place the valence electrons until octet rule is satisfied,
we will be left with 12 lone pairs for phosphate ion.
Answer:
Rb
Explanation:
Second ionization energy is the energy required for the removal of the second loosely bonded valence electron from an isolated gaseous atom.
The given elements:
Rb , Sr, Y and Zr
These are the elements of the fifth period.
The electronic configuration of Rb -
The electronic configuration of Sr -
The electronic configuration of Y -
The electronic configuration of Zr -
<u>When one electron is removed from Rb, the cation attains the noble gas configuration due to which the removal of second electron from Rb is very very difficult. Thus, Rb has the largest second ionization energy.</u>
The values of the second ionization of these elements are:
Rb = 2633 kJ/mol
Sr = 1064.2 kJ/mol
Y = 1180 kJ/mol
Zr = 1270 kJ/mol