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Verizon [17]
3 years ago
6

The most abundant class of phospholipid in animal cell membranes, with a hydrophobic tail composed of two fatty acyl chains, est

erified to the two hydroxyl groups in glycerol phosphate and a polar head group attached to the phosphate group, is called:___________.
Chemistry
1 answer:
juin [17]3 years ago
7 0

Answer:

Phosphatidylcholine also known as lecithin

Explanation:

The most common phospholipids in order of abundance are

1). phosphatidylcholine, lecithin

2). phosphatidylethanolamine, cephalins 3).phosphatidylinositol, and 4).phosphatidylserine.

They have the common characteristics of esterified fatty acids to the 1 and 2 positions of the glycerol structure with the esterified phosphate group to the 3 position

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List three branches life<br>Science and describe what studied in each?​
Mama L [17]

Answer:

First off Life sciences are anything concerned with the study of a living organisms. So ones that would be included would be, microbiology biology, botany, zoology, ecology, genetics and medicine, from what the dictionary states

Explanation:

Biology is the natural science that studies life and living organisms. Which also includes molecular interactions, including their physical structure.

Genetics, is the study of heredity and or the variation of inherited characteristics that we get from family.

Microbiology, is the branch of science which deals with microorganisms.

Let me know if this helps, if not I'll continue researching.

3 0
3 years ago
PLEASE HELP ME! What are some patterns or trends that are present in the table of elements?
Sati [7]

Some patterns and trend that are present in the periodic table would be

1. electronegativity (from left-to-right it increases across the table)

2. ionization (from left-to right it increases and from bottom-to-top it increases)

3. electron affinity (same as ionization energy)

4. atom radius (increases opposite way; from right-to-left it increases and from top-to-bottom it increases)

5. melting point (higher melting points with metals and lower melting point with non-metals)

6. metallic character (same as atom radius)

5 0
3 years ago
10 m3 of carbon dioxide is originally at a temperature of 50 °C and pressure of 10 kPa. Determine the new density and volume of
Dimas [21]

Answer : The new density and new volume of carbon dioxide gas is 0.2281 g/L and 7.2m^3 respectively.

Explanation :

First we have to calculate the new or final volume of carbon dioxide gas.

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 10 kPa

P_2 = final pressure of gas = 15 kPa

V_1 = initial volume of gas = 10m^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 50^oC=273+50=323K

T_2 = final temperature of gas = 75^oC=273+75=348K

Now put all the given values in the above equation, we get:

\frac{10kPa\times 10m^3}{323K}=\frac{15kPa\times V_2}{348K}

V_2=7.2m^3

The new volume of carbon dioxide gas is 7.2m^3

Now we have to calculate the new density of carbon dioxide gas.

PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}

Formula for new density will be:

\rho_2=\frac{P_2M}{RT_2}

where,

P_2 = new pressure of gas = 15 kPa

T_2 = new temperature of gas = 75^oC=273+75=348K

M = molar mass of carbon dioxide gas = 44 g/mole

R = gas constant = 8.314 L.kPa/mol.K

\rho = new density

Now put all the given values in the above equation, we get:

\rho_2=\frac{(15kPa)\times (44g/mole)}{(8.314L.kPa/mol.K)\times (348K)}

\rho_2=0.2281g/L

The new density of carbon dioxide gas is 0.2281 g/L

5 0
2 years ago
Give the orbital notation for a neutral atom of titanium
dedylja [7]

Answer:

Explanation:

A neutral titanium atom will have 22 electrons. Therefore, its electron configuration will be 1s2 2s2 2p6 3s2 3p6 4s2 3d2.

5 0
2 years ago
An 11.75 g sample of a common hydrate of cobalt(ii) chloride is heated. after heating, 9.25 g of anhydrous cobalt chloride remai
Irina-Kira [14]
Hydrated salts are when salt crystals have water molecules bound. Anhydrous salts are when the water has been removed.
mass of water removed = hydrated salt - anhydrate salt 
                                       = 11.75 g - 9.25 g = 2.50 g
number of water moles  = 2.50 g / 18 g/mol = 0.139 mol 
number of cobalt (II) chloride moles = 9.25 g / 130 g/mol = 0.0712 mol 
ratio of water moles to CoCl₂ moles - 0.139 mol / 0.0712 mol = 1.95 
rounded off 2 moles of water for every 1 mol of CoCl₂
formula - CoCl₂.2H₂O
name - Cobalt(II) chloride dihydrate
3 0
2 years ago
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