The object has an overall positive charge.
Answer:
1) The value of Kc:
C. remains the same.
2) The value of Qc:
A. is greater than Kc.
3) The reaction must:
B. run in the reverse direction to restablish equilibrium.
4) The concentration of N2 will:
B. decrease.
Explanation:
Hello,
In this case, by means of the Le Chatelier's principle which is based on the shift a chemical reaction could have under some modifications, we have:
1) The value of Kc:
C. remains the same, since it just depend the reaction's thermodynamics as it is computed via:

2) The value of Qc:
A. is greater than Kc, since the reaction quotient is:
![Qc=\frac{[N_2][H_2]^3}{[NH_3]^2}](https://tex.z-dn.net/?f=Qc%3D%5Cfrac%7B%5BN_2%5D%5BH_2%5D%5E3%7D%7B%5BNH_3%5D%5E2%7D)
Thus, the lower the concentration of ammonia, the higher Qc, making Qc>Kc.
3) The reaction must:
B. run in the reverse direction to restablish equilibrium, since ammonia was withdrawn and should be regenerated to reach the equilibrium.
4) The concentration of N2 will:
B. decrease, since less reactant is forming the products.
Best regards.
Answer: Linear
Explaination: The central atom of a carbon dioxide molecule is carbon. Carbon is tetravalent which just means it has 4 valence electrons. Because the valence shell isn’t full, the carbon atom can bond with other atoms creating a total of 4 bonds. This then allows the carbon to double bond with 2 oxygen atoms. Now, the atoms in the CO2 molecule Don’t share the electrons evenly because of atomic number or proton count. Because oxygen has an atomic number of 6, carbon has an atomic number of 4, and opposites attract (referring to the positivity of the nucleus and the negativity of the shared electrons), the oxygen atoms will have a slightly negative charge (-) and the oxygen will have a slightly positive charge (+ ). Therefore, the slightly negative oxygen atoms repel creating that linear shape.