Answer:
Replicated chromosomes at metaphase I = 66
Sister chromatids at metaphase I = 66 x 2 = 132
Sister chromatids at prophase II = 66
Chromosomes in each sperm cells = 33
Explanation:
Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.
Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.
Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.
Answer:
Please find the complementary pair of each DNA strand below.
1. CTT GTA GTC A
GAA CAT CAG T
2. GGC ATG CTT C
CCG TAC GAA G
3. GAC TTG GTT C
CTG AAC CAA G
4. CTG AAG TGG C
GAC TTC ACC G
Explanation:
DNA is a double-stranded molecule i.e. it consists of two strands that are complementary to one another. According to the complementary base pairing rule, adenine base (A) will always hydrogen pair with Thymine base (T) i.e. A-T while Guanine base (G) will always hydrogen pair with Cytosine base (C) i.e. C-G.
Hence, based on the above explanation of complementary base pairing, the complementary pair of each DNA strand in this question are as follows;
N.B: They are numbered from left to right on the question
1. CTT GTA GTC A
GAA CAT CAG T
2. GGC ATG CTT C
CCG TAC GAA G
3. GAC TTG GTT C
CTG AAC CAA G
4. CTG AAG TGG C
GAC TTC ACC G
Carbon from bicarbonate is used for transformation of acetyl-CoA into malonyl-CoA. Bicarbonate gives only one carbon, and if it would give two (both) carbons, it would be lost. On the other hand, <span>two carbons are necessary </span>for the incorporation into the new fatty acid. So, the reason will be that bicarbonate cannot give an adequate amount of carbons, so it cannot be incorporated into the new fatty acid.