Explanation:
1.
the answer to the first question is <u>organizational unit</u>. this is because in this scenario that we have before us, cost is a deciding factor. a unit as this can adapt to changes, it is flexible and also not very complex
2.
answer to question 2 is <u>PDC emulator</u><u>.</u><u> </u>this emulator can perform the function synchronization of time across every domain controller that is in the domain. other of its functions are, authentication and changing of passwords.
3.
the answer to the 3rd question is <u>child domain</u><u>.</u><u> </u>It is a factor in this scenario because it works well in a situation where there is an issue of slow network connection.
Answer:A) All other answers
Explanation:
Circular linked chain is the type of the linked list formed that has the first component attached to the last component and every other are connected consecutively .
The circular linked list which is in two section is implemented in the form queue by the methods such as the initializing the nodes and using them when there is the requirement of it or it can also keep the node for the future use.
Answer:
The description including its scenario is listed throughout the explanation section below.
Explanation:
Star topology seems to be a LAN system under which all points are connected to a single cable link location, such as with a switch as well as a hub. Put it another way, Star topology is among the most commonly used network configurations.
Throughout this configuration or setup:
- Each common network setups network unit, such as a firewall, switch, as well as computer.
- The main network computer serves as either a server as well as the peripheral system serves as just a client.
Answer:
The following Window class are given below:
class Window // define a class Window
{
private: //access modifier
int width, height; // integer type variable which is width and height
public: //access modifier
Window(int w,int h) //constructor that accepts two integer parameters
{
width = w;
height = h;
}
friend bool areSameSize(Window a, Window b)
{
if ((a.height == b.height) && (a.width == b.width))
return true;
else return false;
}
};
Explanation:
According to the question: Firstly we have define a class which name is 'Window' and then we take two integer type data member and after that we have constructor that takes two integer type parameters and after all we have a areSameSize, friend function, which can take two objects and then it give output in the form of true or false, if they are the equal size and finally we check that if the width and the height match then it returns the true and else it returns the false
