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sveta [45]
3 years ago
8

I’m confused how do you know where to put the plus and minus signs when rearranging the equation?

Mathematics
1 answer:
IRINA_888 [86]3 years ago
7 0
-5/12k +29/36m is simplified
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How are a common denominator and a common multiple alike and different?
victus00 [196]
East common multiple is the smallest multiple both numbers can go into. (Example: the LCM of 10 and 4 is 20, because both 10 and 4 go into 20 and 20 is the smallest number both 10 and 4 can go into. You could just multiply them both, but you'd get 40 and since its a bigger number it would be harder to work with.)

<span>Least common denominator is just the least common multiple as a denominator. (Example: if you wanted to find the LCD of 5/7 and 1/10, you'd have to find the LCM of the demoniators (7 and 10) and then just use that as the denominator when adding fractions with unlikely denominators.) Sorry for such a long answer :P</span>
3 0
3 years ago
Read 2 more answers
A music store has sold 3/5 of their hip-hop CDs, but 10 were returned.Now the store has 62 Hip-Hop CDs,How many Hip-Hop CDs did
kow [346]

Answer: 130

Step-by-step explanation:

Let x be the original number of hip- hop CDs in the music store.

Given : A music store has sold 3/5 of their hip-hop CDs, but 10 were returned.

i.e. The number of hip- hop CDs in the store  will be :

Original No. of CDs - CDs sold + CDs Returned

x-\dfrac{3}{5}x+10

If  the store has 62 Hip-Hop CDs now , then required euation will be :-

x-\dfrac{3}{5}x+10=62

Subtract 10 from both sides , we get

x-\dfrac{3}{5}x=52

\Rightarrow\ \dfrac{5x-3x}{5}=52

\Rightarrow\ \dfrac{2x}{5}=52

\Rightarrow\ x=52\times\dfrac{5}{2}=130

Hence, the number of CDs they originally have = 130

7 0
3 years ago
Emily is observing the velocity of a cyclist at different times. After four hours, the velocity of the cyclist is 14 km/h. After
lina2011 [118]
Assume that Emily starts from rest so that the velocity is zero at 0 hours.

Define the function v(t) for velocity in km/h, and t in hours.

Part A
From t=0 to t=4, v changes from 0 to 14.
Let v(t) = mt + b
The slope is
  m = 14/4 = 3.5, and the y-intercept is
  b = 0.
Therefore
v(t) = 3.5t,  for 0 ≤ t ≤ 4

Fromt=4 to t=9,  changes from 14 to 4.
Let v(t) = mt + b
The slope is
  m = (4 - 14)/(9 - 4) = -2
Therefore
  v = -2t + b
When t=4, v=14, therefore
 14 = -2*4 + b = -8 + b
 22 = b
v(t) = -2t + 22, for 4 < t ≤ 9.

Answer:
The equation for the velocity is
v(t) = 3.5t,  0 ≤ t ≤ 4
      = -2t + 22,  4 < t ≤ 9

Part B
The equation for velocity is a piecewise function that is graphed as shown below. If we assume that the second part of the equation is valid at t=10, then
v(10) = -2*10 + 22 = 2 km/h

3 0
3 years ago
Which question is a statistical question?
Gwar [14]

Answer:

C. How many movies do the students in my class watch in a month

Step-by-step explanation:

7 0
3 years ago
Jermaine, Keira, and Leon are buying supplies for an art class. Jermaine bought 2 canvases, 4 tubes of paint, and 2 paint brushe
maria [59]

Answer:

canvas $3

tube of paint $5

paint brush $4

Step-by-step explanation:

We need to choose variables for the prices of the different items, translate the sentences into equations, and solve a system of equations.

1. Define variables

Let c = price of 1 canvas, t = price of 1 tube of paint, and b = price of 1 brush.

2. Translate sentences into equations

"Jermaine bought 2 canvases, 4 tubes of paint, and 2 paint brushes for $34."

2c + 4t + 2b = 34

"Keira spent $22 on 1 canvas, 3 tubes of paint, and 1 paint brush."

c + 3t + b = 22

"Leon already has plenty of paint, so he bought 3 canvases and 2 paint brushes for $17."

3c + 2b = 17

The system of equations is

2c + 4t + 2b = 34       Eq. 1

c + 3t + b = 22           Eq. 2

3c + 2b = 17               Eq. 3

Since the third equation has only the variables c and b, we use the first equations to eliminate variable t and give us an equation in only c and b.

3 * Eq. 1 - 4 * Eq. 2

2c + 2b = 14

c + b = 7            Eq. 4

Eq. 3 and Eq. 4 form a system of equations in two variables.

3c + 2b = 17      Eq. 3

c + b = 7          Eq. 4

Solve Eq. 4 for b.

b = 7 - c        Eq. 5

Substitute into Eq. 3.

3c + 2(7 - c) = 17

3c + 14 - 2c = 17

c = 3

Plug in c = 3 into Eq. 5.

b = 7 - 3

b = 4

Plug in c = 3 and b = 3 into Eq. 2.

c + 3t + b = 22           Eq. 2

3 + 3t + 4 = 22

3t + 7 = 22

3t = 15

t = 5

Answer:

canvas $3

tube of paint $5

paint brush $4

7 0
3 years ago
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