Question

Does anyone understand this?. I also have to show my work.

Answer 1

Answer:

Ans A). The graph is shown.

Ans B). 18.3333 C temperature when F is 65 temperature

Ans C). 32 F when the line crosses the horizontal axis

Ans D). Slope of line C=$\frac{5}{9}(F -32)$ is $\frac{5}{9}$

Step-by-step explanation:

Given equation is C=$\frac{5}{9}(F -32)$

Ans A).

For the table,

Take the four value of F as 32,41,50,59.

For F = 32.

The value of C is

C=$\frac{5}{9}(F -32)$

C=$\frac{5}{9}(32 -32)$

C=0.

For F = 41.

The value of C is

C=$\frac{5}{9}(F -32)$

C=$\frac{5}{9}(41 -32)$

C=05

For F = 50.

The value of C is

C=$\frac{5}{9}(F -32)$

C=$\frac{5}{9}(50 -32)$

C=10

For F = 59.

The value of C is

C=$\frac{5}{9}(F -32)$

C=$\frac{5}{9}(32 -32)$

C=15

Note: The figure shows a graph of given equation with points.

Ans B). Estimate temperature in C when the temperature in F is 65

For F = 65.

The value of C is

C=$\frac{5}{9}(F -32)$

C=$\frac{5}{9}(32 -32)$

C=18.333333.

Ans C). At what temperature, graph lien cross the horizontal axis

When the line crosses the horizontal axis, C=0

Therefore,

C=$\frac{5}{9}(F -32)$

0=$\frac{5}{9}(F -32)$

0=$(F -32)$

F=32 Temperature.

Ans D). Slope of the line C=$\frac{5}{9}(F -32)$

The slope of line is given by s= $\frac{Y1-Y2}{X1-X2}$

Take points from the table of answer A.

let (32,0) and (41,5) using for slope.

s= $\frac{Y1-Y2}{X1-X2}$

s= $\frac{0-5}{32-41}$

s= $\frac{5}{9}$

Slope of line C=$\frac{5}{9}(F -32)$ is $\frac{5}{9}$