Answer:
CasH52(1) + 38 O2(g) → 25 CO2(g) + 26 H2O(g)
Explanation:
Answer:
The mass percentage of calcium carbonated reacted is 2.5%.
Explanation:
The reaction is:
Thus the Kp of the equilibrium will be:
Kp = partial pressure of carbon dioxide [as the other are solid]
Moles of calcium carbonate initially present = 
Let us apply ICE table to the equilibrium given:
Initial 0.2 0 0
Change -x +x +x
Equilibrium 0.2-x x x
Kp = partial pressure of carbon dioxide
Kp = Kc(RT)ⁿ
where n = difference in the number of moles of gaseous products and reactants
for given reaction n = 1
R = gas constant = 8.314 J /mol K
T = temperature = 800 ⁰C = 1073 K
Putting values
Kc =
Kc = ![\frac{[CO_{2}][CaO]}{[CaCO_{3}]}= \frac{x^{2} }{(0.2-x)}=1.3X10^{-4}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCO_%7B2%7D%5D%5BCaO%5D%7D%7B%5BCaCO_%7B3%7D%5D%7D%3D%20%5Cfrac%7Bx%5E%7B2%7D%20%7D%7B%280.2-x%29%7D%3D1.3X10%5E%7B-4%7D)
On calculating
x = 0.005
where x = the moles of calcium carbonate dissociated or reacted.
Percentage of the moles or mass reacted = 
%
Answer:
1835 J
Explanation:
There are three heat flows in this question.
Heat lost by Fe + heat gained by water + heat gained by calorimeter = 0
q₁ + q₂ + q₃ = 0
m₁C₁ΔT₁ + m₂C₂ΔT₂ + q₃ = 0
Data:
m₁ = 65.06 g
C₁ = 0.450 J·°C⁻¹g⁻¹
Ti = 100.0 °C
T_f = 23.59 °C
m₂ = 32.49 g
C₂ = 4.184 J·°C⁻¹g⁻¹
Ti = 20.63 °C
T_f = 23.59 °C
Calculations:
(a) Heat lost by iron
ΔT₁ = 23.59 °C - 100.0 °C = -76.41 °C
q₁ = m₁C₁ΔT₁ = 65.06 g × 0.450 J·°C⁻¹g⁻¹ × (-76.41 °C) = -2237 J
(b) Heat gained by water
ΔT₂ = 23.59 °C - 20.63 °C = 2.96 °C
q₂ = m₂C₂ΔT₂ = 32.49 g × 4.184 J·°C⁻¹g⁻¹ × 2.96 °C = 402 J
(c) Heat gained by calorimeter
-2237 J + 402 J + q₃ = 0
-1835 J + q₃ = 0
q₃ = 1835 J
The heat gained by the calorimeter was 1835 J.
Answer:
In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.
<u>Location One: Select two events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:
</u>
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
<u>Location Two: Select three events that you predict will be observed. If I explore two continental plates at a divergent boundary, then I will observe:
</u>
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
<u>Location Three: Select three events that you predict will be observed. If I explore two continental plates at a transform boundary, then I will observe:
</u>
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
<em><u>This is all I have for now! Hope this can help! :)</u></em>
Answer:
See explanation
Explanation:
Heat of formation, also called standard heat of formation, enthalpy of formation, or standard enthalpy of formation, the amount of heat absorbed or evolved when one mole of a compound is formed from its constituent elements, each substance being in its normal physical state (gas, liquid, or solid)(Encyclopedia Britannica).
The greater the magnitude of the negative value of the heat of formation(the more negative), the greater stability of the compound formed. Hence, a more negative heat of formation (a larger negative number) means that a compound is more stable than an isomer with a less negative heat of formation.
