Answer:
The acceleration of the car is 9,19 m/s2
Explanation:
We use the formula: F=m x a---> a=F/m
a=21,6N/ 2,35kg 1N is 1kgxm/s2
a=21,6 kg x m/s2 x 2,35 kg
a=9,191489362 m/s2
Thomson's model included Protons and Electrons. His model is referred to as 'Plum Pudding' because of it.
Aluminum is 26.982 grams per mole, so 26.982/19.9 will give you the moles 1.3558794
Basis of the calculation: 100g
For Carbon:
Mass of carbon = (100 g)(0.80) = 80 g
Number of moles of carbon = (80 g)(1 mole / 12g) = 20/3
For Hydrogen:
Mass of hydrogen = (100 g)(0.20) = 20 g
Number of moles of hydrogen = (20 g)(1 mole / 1 g) = 20
Translating the answer to the formula of the substance,
C20/3H20
Dividing the answer,
CH3
The molar mass of the empirical formula is:
12 + 3 = 15 g/mol
Since, the molar mass given for the molecular formula is 30.069 g/mol, the molecular equation is,
C2H6
ANSWER: C2H6
Answer:
This is a coal combustion process and we will assume
Inlet coal amount = 100kg
It means that there are
15kg of H2O, 2kg of Sulphur and 83kg of Carbon
Now to find the mole fraction of SO2(g) in the exhaust?
Molar mass of S = 32kg/kmol
Initial moles n of S = 2/32 = 0.0625kmols
Reaction: S + O₂ = SO₂
That is 1 mole of S reacts with 1 mole of O₂ to give 1 mole of SO₂
Then, it means for 0.0625 kmoles of S, we will have 0.0625 kmole of SO2 coming out of the exhaust
The mole fraction of SO2(g) in the exhaust=0.0625kmols
Explanation:
