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inessss [21]
3 years ago
13

Carl rented a bounce house for his little brother's birthday party. The company charges a base rental charge of $95.25, plus a c

ertain amount per hour. Carl's little brother's party lasted 4 hours, and costs $179.72. Carl plans to rent a bounce house for his little sister's birthday party for 6 hours for about $200. Is this a reasonable estimate? A. Yes, the estimate is reasonable. B. No, the estimate should be lower. C. No, the estimate should be higher.
Mathematics
1 answer:
Law Incorporation [45]3 years ago
7 0

Answer:

C. No, the estimate should be higher.

Step-by-step explanation:

Carl's brother party

Fixed charge = $95.25

Number of hours = 4 hours

Hourly charge = x

Total cost = $179.72

179.72 = 95.25 + 4x

179.72 - 95.25 = 4x

84.47 = 4x

x = 84.47/4

x = 21.1175

Hourly charge = $21.1175

Carl's little sister party

Estimated total charge = $200

Number of hours = 6

Fixed charge = $95.25

Hourly charge = $21.1175

Total charges = 95.25 + 6(21.1175)

= 95.25 + 126.705

= 221.955

Total charges = $221.955

C. No, the estimate should be higher

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Answer: $10

Step-by-step explanation:

Let adults tickets be denoted by a

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5a + 12s = 160

We combine both equations

10a + 11s = 190 .......... equation i

5a + 12s = 160 ........... equation ii

Multiply equation i by 5

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50a + 55s = 950 ....... equation iii

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Subtract equation iv from iii

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3 years ago
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three more than the sum of (3,3)

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The surface area of a triangular pyramid is 1,936 inches squared. If the dimensions are multiplied by 1/4, what will be the new
rosijanka [135]

Answer:

121 inches squared

Step-by-step explanation:

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Find an expression for the nth term (t_n) in each of the following​
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<h3><u>Answer:</u></h3>

\boxed{\pink{\tt\longmapsto The \ nth \ term \ of \ the \ sequence\ is \ given \ by \frac{1}{n}}}

<h3><u>Step-by-step explanation:</u></h3>

A sequence is given to us is , and we need to find expression for nth term of the sequence. The given sequence is ,

\boxed{\boxed{\blue{\qquad\bf 1 , \dfrac{1}{2},\dfrac{1}{3},\dfrac{1}{4},\dfrac{1}{5},\dfrac{1}{6}}}}

When we flip the numbers , we can clearly see that the number are in Harmonic Progression.

That is when we flip the numbers they are found to be in Arithmetic Progression .

And nth term of an Harmonic Progression is :-

\boxed{\purple{\bf T_{(Harmonic \ Progression)} = \dfrac{1}{a+(n-1)d}}}

Hence here

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\bf\implies T_{n}= \dfrac{1}{a+(n-1)d} \\\\\bf\implies T_{n} = \dfrac{1}{1+(n-1)1}\\\\\bf\implies T_n = \dfrac{1}{1+n-1}\\\\\bf\implies\boxed{\red{\bf T_{n}=\dfrac{1}{n}}}

<h3><u>Hence the nth term of the given sequence is given by ¹/n .</u></h3>

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