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nignag [31]
3 years ago
7

I need help solving this 8

Mathematics
2 answers:
ch4aika [34]3 years ago
7 0
8 < x+3 = 8-3 < x =5X+3< 12 = x<12-3 = x<9
vlabodo [156]3 years ago
6 0

Answer:

whats the question?

Step-by-step explanation:


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A school has 17 tables in the cafeteria. Each table seats 12 students. What is the
Scorpion4ik [409]

Answer: 204 students

Step-by-step explanation: To find  out the greatest number of students that can fit at the 17 tables in the school cafeteria, we simply need to multiply the number of students that can fit at each table by the number of tables.

12 students can fit at 1 table and there are 17 tables.

So we have (12)(17) which is 204.

So the greatest number of students that can be seated din the cafeteria is 204 students.

8 0
3 years ago
Read 2 more answers
Find the area of the shaded region .
klasskru [66]
Area of the shaded region=area of the greater rectangle- area of the inner rectangle.

Area of a rectangle=length x width.

Area of the greater rectangle=(8x-1)(6x)
area of the inner rectangle=(5x+3)(2x)

Area of the shaded region=(8x-1)(6x)-(5x+3)(2x)
=48x²-6x-(10x²+6x)
=48x²-6x-10x²-6x
=38x²-12x

Answer: the area of the shaded region would be: 38x²-12x
8 0
3 years ago
Solve x^2-3x=-8 PLEASE HELP ALGEBRA 2
Delvig [45]

Answer:

idk aljebra 2 either and i just got the same question how?

Step-by-step explanation:

5 0
3 years ago
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
Plz help me with #23 and #41
GuDViN [60]
23) 17/30

41) 3/10 because 3/10 + 7/10 = 10/10 or 1.
7 0
3 years ago
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