Answer:Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number. So, for instance, 2728 has alternating sum of digits 2 – 7 + 2 – 8 = -11. Since -11 is divisible by 11, so is 2728.
Hope this helped
Answer:
<em>1.5880 × 10¹.</em>
Step-by-step explanation:
Answer:
x = ±2√5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Terms/Coefficients
- Multiple Roots
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
4x² - 5 = 75
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Addition Property of Equality] Add 5 on both sides: 4x² = 80
- [Division Property of Equality] Divide 4 on both sides: x² = 20
- [Equality Property] Square root both sides: x = ±2√5
Answer:
r = -1
Step-by-step explanation:
(y2-y1)/(x2-x1)=m
(r,7)=(x1,y1) and (3,4)=(x2-y2) and m=-3/5
so plug in...
(4-7)/(4-r)=-3/5
then solve for r which will get that r = -1
numerator: 4-7=-3
denominator: 4-r=5 -> 4-5=0+r -> -1=r
Answer:
Step-by-step explanation:
f(x) = 4-x
g(x) = h
+k
g(f(x)) = 2-16x+26
so put f(x) in g(x)
h
+k
h((4-x)(4-x) + k
h(-8x+16)+k
if h = 2 , then
2-16x+32 + k
and we want 26 instead of 32 so subtract 6 so K = (-6)
2-16x+32 + (-6)
2-16x+32 - 6
2-16x+26
h=2
k=(-6)
