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3 years ago

What is...............2(4x-3)-8=4+2x

Mathematics

1 answer:

Lyrx [107]3 years ago

7 0

Answer:

$\huge\boxed{x=3}$

Step-by-step explanation:

$\text{Solve the equation for 'x'.}\\\\\\2(4x-3)-8=4+2x\\\\8x-6-8=4+2x\\\\8x-14=4+2x\\\\8x-14+14=4+14+2x\\\\8x=18+2x\\\\8x-2x=18+2x-2x\\\\6x=18\\\\\frac{6x=18}{6}\\\\\boxed{x=3}\\\\\\\boxed{\text{The correct answer should be: } X= 3}\\\\\\\text{Hope this helps you!}$

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2 years ago

It took Samantha 324 minuets to cook an 18 pound turkey. How many minutes per pound did it take to cook the turkey

Natalka [10]

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3 years ago

Which point lies on the graph of the equation 10y = 3x - 11?

GaryK [48]

Answer:

A. (2,-0.5)

Step-by-step explanation:

A pair of coordinates is always (x,y) so

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3 years ago

What is the volume of a rectangular prism that has a length of 18 inches, a width of 1 foot, and a height of 14 inches?

Ede4ka [16]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

In a study of wait times at an amusement park, the most popular roller coaster has a mean wait time of 17.4 minutes with a stand

Ann [662]

Answer: A: 0.0031

Step-by-step explanation:

Given : In a study of wait times at an amusement park, the most popular roller coaster has a mean wait time of 17.4 minutes with a standard deviation of 5.2 minutes.

i.e. $\mu=17.4$ and $\sigma=5.2$

We assume that the wait times are normally distributed.

samples size : n= 30

Let x denotes the sample mean wait time.

Then, the probability that the mean wait time is greater than 20 minutes will be :

$P(x>20)=1-P(x\leq20)\\\\=1-P(\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}\leq\dfrac{20-17.4}{\dfrac{5.2}{\sqrt{30}}})\\\\=1-P(z\leq2.74)\ \ [\because\ z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=1-0.9969\ \ [\text{ By z table}]\\\\=0.0031$

Hence, the probability that the mean wait time is greater than 20 minutes.= 0.0031

Thus , the correct answer is A: 0.0031 .

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3 years ago