3 years ago

Write an equation of a parabola with a vertex at the origin and a directx at y=5

1 answer:

4 0

Directrix at y=5 (horizontal line) → The parabola is vertical
Vertex at the orgin: V=(0,0)=(h,k)→h=0, k=0
The directix is above the vertex→the parabola opens downward→p is negative
p is the distance between the vertex and the directrix→p=-5
Equation has the form:
(x-h)^2=4p(y-k)
(x-0)^2=4(-5)(y-0)
x^2=-20y

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