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stealth61 [152]
3 years ago
8

-6y^2 + 9y^2 - y - 9 - 7y^2 + 1 + 10y + 3y

Mathematics
2 answers:
Simora [160]3 years ago
7 0

Answer:

-4y² + 12y - 8

Step-by-step explanation:

-6y² + 9y² - y - 9 - 7y² + 1 + 10y + 3y

-6y² + 9y² - 7y² - y + 10y + 3y - 9 + 1

-4y² + 12y - 8

taurus [48]3 years ago
6 0

Answer: -4y^(2)+12y-8

Step-by-step explanation: Combine like terms

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Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.
Levart [38]

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4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Step-by-step explanation:

We know that:

4p\left(y-k\right)=\left(x-h\right)^2 is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

x^2\:+\:10x\:+\:6y\:=\:47

Rewriting the equation in the standard form

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

where

vertex (h, k) = (-5, 12)

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3 years ago
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