Question

9th grade ..Plz solve this maths​

Answer 1

since the polygon has 8 chambers the angle of one chamber = 360/8 = 45°

so the angle WOP = 45°

now drawing a imaginary line which seperates the triangleWOP into half

so the angle of imaginary line is 45/2 = 22.5

sin(theta) = opp/hyp

since WP (opp) is unknown. take as x

sin(22.5) = x/44

0.383×4 = x

x = 1.532 (app) = 1.5 cm

perimeter = 1.5 × 8

= 12 cm

area of triangle WOP = 2×1/2 ×bh = bh

= 4×1.5

= 6 cm²

so the area of regular polygon = 8× area of a triangle

= 48 cm²