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3 years ago

syeda has finished 20% of her math assignment. The assignment includes 50 problems how many problems has syeda completed?

Mathematics

1 answer:

Nostrana [21]3 years ago

5 0

Answer:

10 problems

Step-by-step explanation:

This is the answer because:

1) We have to solve for what 20% of 50 is since she finished 20% of her test:

20% of 50 = 10

$\frac{2}{10}$ × $\frac{50}{1}$ = $\frac{100}{10}$ = 10

Therefore, the answer is 10 problems.

Hope this helps! :D

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The function y=-16t^2 +36 represents the height y (in feet) of a water droplet t seconds after falling from an icicle. After how

NikAS [45]

Answer:

1.5 seconds

Step-by-step explanation:

plug 0 in for y

0=-16t^2+36

then slove for t

-36=-16t^2

-36 / -16 = 9/4

9/4=t^2

square root of 9/4 is 3/2 or 1.5

t=1.5

3 0

2 years ago

What is the range of the function f(x) = -2(6^x) +3?<br><br><br> Answer is B

Oksana_A [137]

Answer:

You are right

Step-by-step explanation:

5 0

3 years ago

Please help quick!!

luda_lava [24]

C
6x^2-13X-5=0
(3X+1)(2X-5)
3x-1=0
X=1/3. 2x-5=0. X= 5/2

7 0

3 years ago

Read 2 more answers

Nola purchased 2.5 pounds of cheese for $10.50. Her mother purchased 3 pounds of the same cheese for $12.60. The cost of cheese

jeka94

Answer:

cost per pound = $4.20

Step-by-step explanation:

Cheese cost per pound = ?

first for the cost per pound

cost per pound = total cost / pounds bought

cost per pound = $10.50 / 2.5 pounds

cost per pound = $4.20

to check the above answer is correct

cost per pound = total cost / pounds bought

cost per pound = $12.60 / 3 pounds

cost per pound = $4.20

Therefor, the cheese costs $4.20 per pound.

4 0

3 years ago

WILL GIVE BRAINLIEST: What is the local minimum value of the function g(x)=x^4-5x^2+4? (Round answer to the nearest hundredth)

IrinaK [193]

Answer:

Step-by-step explanation:

you can find where the first derivative is 0 to find the critical points

g'(x) = ( x^4 -5x^2 +4)' = 4x³-10x

g'(x) =0, make y =0 to find find where g'(x) is 0

4x³-10x =0 , factor 2x

2x(2x²-5)= 0 , each factor must be 0

2x= 0, so x= 0

2x²-5 =0, so x = ±√5/2

we now have 3 critical points -√5/2, 0, and √5/2

make intervals (-∞, -√5/2), (-√5/2, 0) , (0, √5/2) and (√5/2, +∞)

pick a point to test on each interval: -2, -1, 1 and 2 for example, and

calculate g'(x) = 4x³-10x at those points

for x= -2 we have 4(-2)³-10(-2) = -12 , negative number, decrease

for x= -1 we have 4(-1)³-10(-1) =6, positive number, increase

for x= 1 we have 4(1)³-10(1) = -6, negative number, decrease

for x= 2 we have 4(2)³-10(2) = 12, positive number, increase

we went from a decrease to an increase on intervals (-∞, -√5/2), (-√5/2, 0) so x= - √5/2 ≈ -1.58 is a minimum

we went from a decrease to an increase on intervals (0, √5/2), (√5/2, +∞) so

x= √5/2 ≈ 1.58 is a minimum as well

4 0

3 years ago