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padilas [110]
3 years ago
10

A company plans to build a metal tool box with a length of 19 inches, a width of 8 inches, and a height of 7 inches. What is the

minimum number of square inches of metal required to build the box?
341
378
682
1064
Mathematics
1 answer:
Lina20 [59]3 years ago
5 0

Answer:

the answer is 1064 u just multiple all the numbers you have since it's a box

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Answer:

k =(2,1)

JK = 2

Step-by-step explanation:

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J = (0,1) ---- (x_1,y_1)

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I = (3,-2) --- (x_3,y_3)

See attachment for grid

Solving (a): The coordinates of K

The parallelogram has the following diagonals: IJ and HK

Diagonals bisect one another. So:

Midpoint of IJ = Midpoint of HK

This gives:

\frac{1}{2}(I + J) = \frac{1}{2}(H+K)

\frac{1}{2}(x_3+x_1,y_3+y_1) = \frac{1}{2}(x_2+x,y_2+y)

\frac{1}{2}(3+0,-2+1) = \frac{1}{2}(1+x,-2+y)

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Multiply through by 2

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By comparison:

1 + x = 3

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y = -1 +2 = 1

So, the coordinates of k is:

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The length of JK is calculated using distance (d) formula

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2

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k =(2,1) ---- (x_2,y_2)

So:

d = \sqrt{(0 - 2)^2 + (1 - 1)^2

d = \sqrt{(- 2)^2 + (0)^2

d = \sqrt{4 + 0

d = \sqrt{4

d = 2

Hence:

JK = 2

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