Answer:
The wall is 90 meters wide.
Step-by-step explanation:
1. set up and solve a proportion to find the value of w like this:
1cm=6cm
15m=wm
2. cancel out the like units on both sides of the equation
1=6
15=w
3. Equate the cross products, and then solve for w:
1*w=15*6
w=90 The actual width of the wall is 90 meters.
Answer:
22 + 27 = <u><em>49</em></u>
<u><em></em></u>
:) :)
Well knowing that the terminal arm of the standard position angle is in quadrant 2, we can determine the reference angle, in quadrant 2, by simply taking the difference between 180 and whatever the angle is.
So ø reference = 180 - ø in standard position.
Regardless, the reference angle is in quadrant 2, we need to then label the sides of the reference triangle based on the opposite and hypotenuse.
Solve for adjacent side using Pythagoras theorem.
A^2 = C^2 - B^2
A^2 = 3^2 - 2^2
A^2 = 9 - 4
A^2 =5
A = sq root of 5.
Then write the cos ratio using the new side.
Cos ø =✔️5/3. Place a negative in front of cos ø as cos is negative in second quadrant.
Thanks i think the answer is c but im not 100% sure
