Answer:
You didn't include any graphs.
Step-by-step explanation:
Answer:
Yes, △ABC ∼ △FED by AA postulate.
Step-by-step explanation:
Given:
Two triangles ABC and FED.
m∠A = m∠B
m∠C = m∠A + 30°
m∠E = m∠F = 
m∠D =
°.
Now, let m∠A = m∠B = 
So, m∠C = m∠A + 30° = 
Now, sum of all interior angles of a triangle is 180°. Therefore,
m∠A + m∠B + m∠C = 180

Therefore, m∠A = 50°, m∠B = 50° and m∠C = m∠A + 30° = 50 + 30 = 80°.
Now, consider triangle FED,
m∠D+ m∠E + m∠F = 180

Therefore, m∠F = 50°
m∠E = 50° and
m∠D = 
So, both the triangles have congruent corresponding angle measures.
m∠A = m∠F = 50°
m∠B = m∠E = 50°
m∠C = m∠D = 80°
Therefore, the two triangles are similar by AA postulate.
The answer is 0.67, simply show your work subtracting then and you get that number, it’s basic subtraction, only you have to count the decimal points to put them in the correct spot
Let the function be y = ax + c.
For (-1,8), 8 = a(-1) + c → 8 = - a + c
For (5,6), 6 = a(5) + c → 6 = 5a + c
Subtract one from abother,
2 = - 6a => - 1/3 = a
Hence, 8 = - 1/3 + c → 23/3 = c
Relation is:
y = (-1/3)x + (23/3)
3y = - x + 23
3y = 23 - x