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charle [14.2K]
3 years ago
6

How does the degree relate to the extrema?

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
5 0
I'm assuming this is for apolynomial function. The question of whether a degreee is odd or even changes the look of a graph. An even-numbered degree forms a parabola, where (in the most basic form), the one minimum point (extrema) just touches the origin. An odd-numbered degree, in its most basic form, doesn't touch a point, it crosses it. It expands infinitely without extrema.

Let's assume you're just talking about quadratic functions (or [even] parabolic functions, to be more general), in which case something like x^2 (the simplest quadratic equation) and x^50 would have the same extreme minimum point.
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What is greater, 3/5r 4/10?
DanielleElmas [232]
3/5 = .6 and 4/10 = .4, so 3/5 is greater than 4/10
7 0
3 years ago
PLSSS HELP!!! 40 pts!!!!
quester [9]

Answer:

∠1=135°

∠2=45°

∠3=45°

∠4=135°

∠5=135°

∠6=45°

∠7=45°

∠8=135°

Step-by-step explanation:

→∠1=∠4[Being vertically opposite angles]

→∠4=135°

→∠1=∠5[Corresponding angles]

→∠5=135°

→∠5=∠8[Being vertically opposite angles]

→∠8=135°

→∠1+∠2=180°[Sum of linear pair]

→∠2=180°-135°

→∠2=45°

→∠2=∠3[Being vertically opposite angles]

→∠3=45°

→∠3=∠6[Alternate angles]

→∠6=45°

→∠6=∠7[Being vertically opposite angles]

→∠7=45°

3 0
3 years ago
Read 2 more answers
∫<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bxdx%7D%7B%28x%5E%7B2%7D%2B4%29%5E%7B3%7D%20%7D" id="TexFormula1" title="\frac{xdx}{
photoshop1234 [79]

Substitute u=x^2+4 and du=2x\,dx. Then the integral transforms to

\displaystyle \int \frac{x\,dx}{(x^2+4)^3} = \frac12 \int \frac{du}{u^3}

Apply the power rule.

\displaystyle \int \frac{du}{u^3} = -\dfrac1{2u^2} + C

Now put the result back in terms of x.

\displaystyle \int \frac{x\,dx}{(x^2+4)^3} = \frac12 \left(-\dfrac1{2u^2} + C\right) = -\dfrac1{4u^2} + C = \boxed{-\dfrac1{4(x^2+4)^2} + C}

3 0
2 years ago
3)A ball is kicked from a height of 2 feet off the ground, after 1 second the ball rea
MArishka [77]

Answer:

y = - 2x + (1/2 38) + 2   = y =  -2x + 19x + 2  at any second  and y = -2x^2 / 2  + 19/2 + 2/2 = <u>- x^2 + 19/2 + 2 </u>=  - x (4) + 19/2(4) + 1 = -4+ 38 + 1 = 35 seconds  

Step-by-step explanation:    We see that 38-2ft = 36ft and y intercept  = 2 and then -2x allows us to represent the starting point 2 as -2 (1) to allow a descend to our back to 0 for y  one we find y intercept we know - x^2  is our simplified equation and an input into this to find the static and slowed descend back to 0  if you keep inputting at 5 and 6 you see the equation speed up   Anyway at (4) substitute = 4 seconds we divide our simplified equation a = -x2 into  a b c and divide each by 2  before working out the<u> </u><u>decline</u> of the equation<u> (as equation still represents all ascending and descending) </u>for the 4th second as the height was <u>already said to be at its max at 38 feet see equation in answer to find 4 as substitute for x </u>

3 0
2 years ago
I need some help!! plss
3241004551 [841]

Answer:

250

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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