Answer:
The Beer–Lambert law, also known as Beer's law, the Lambert–Beer law, or the Beer–Lambert–Bouguer law relates the attenuation of light to the properties of the material through which the light is travelling.
Explanation:
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Answer: It is C I just did this question in math class
Explanation:
Answer:
State of matter is defined as a form in which matter can exist. There are four states of matter known till date. They are as follows:
Solid: Matter is said to be in solid state if it has definite shape and volume. The components of matter are closely packed and have fixed positions within the matter.
Liquid: In liquid state, matter has fixed volume but shape is not fixed, it takes the shape of container in which it is placed. The particles of liquid are close but can move freely or do not have fixed positions.
Gas: Matter in gaseous state has variable volume and shape. The particles of gas are very far from each other thus, they are in constant motion without any fixed position..
Plasma: This state of matter has variable shape and volume. It has neutral atoms, the number of ions and electrons are significant and can move freely in the matter. In order to make plasma, energy is required to strip electron from atom.
According to above definitions, the state of matter is matched with the given statements as follows:
Plasma-Particles are so hot that electrons are stripped from atoms.
Gas-It expands to fill the volume of the container.
Liquid-Particles move past each other freely but do not go fat apart.
Solid-It retains its shape regardless of the shape of the container.
Explanation:
I choose this because It understands how each plasma work.
The given sentence is part of a longer question.
I found this question with the same sentence. So, I will help you using this question:
For the reaction N2O4<span>(g) ⇄ 2NO</span>2(g), a reaction mixture at a certain temperature initially contains both N2O4 and NO2 in their standard states (meaning they are gases with a pressure of 1 atm<span>). If </span>Kp = 0.15, which statement is true of the reaction mixture before
any reaction occurs?
(a) Q = K<span>; The reaction </span>is at equilibrium.
(b) Q < K<span>;
The reaction </span>will proceed to
the right.
(c) Q > K<span>; The reaction </span>will proceed to the left.
The answer is the option (c) Q > K<span>; The reaction will proceed to the </span>left,
since Qp<span> = </span>1<span>, and 1 > 0.15.</span>
Explanation:
Kp is the equilibrium constant in term of the partial pressures of the gases.
Q is the reaction quotient. It is a measure of the progress of a chemical reaction.
The reaction quotient has the same form of the equilibrium constant but using the concentrations or partial pressures at any moment.
At equilibrium both Kp and Q are equal. Q = Kp
If Q < Kp then the reaction will go to the right (forward reaction) trying to reach the equilibrium,
If Q > Kp then the reaction will go to the left (reverse reaction) trying to reach the equilibrium.
Here, the state is that both pressures are 1 atm, so Q = (1)^2 / 1 = 1.
Since, Q = 1 and Kp = 0.15, Q > Kp and the reaction will proceed to the left.
