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padilas [110]
3 years ago
11

What does Bromine-80 decays by beta decay to?

Chemistry
1 answer:
nlexa [21]3 years ago
7 0

Answer:

beta to Kr-80 or Se-80

Explanation:

sorry if wrong

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What information could a student determine from only the chemical formula of a protein
Rama09 [41]
The number of atoms of each element in the protein
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3 years ago
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What is the pressure exerted by a force of 15.0 N over an area of 0.00372 m^2 ?
aleksandrvk [35]

Explanation:

Pressure = Force/Area

therefore,

P = 15/0.00372

= 4.03 X10^³N/m²

6 0
2 years ago
Calculate the volume of 2.408x1024 molecules of water vapor at STP.
Tom [10]

Answer:

B

Explanation: im not rlly sure you can go with what i said or you dont

8 0
3 years ago
PRACTICE
Stels [109]

Answer:

35.8 u

Explanation:

The atomic mass of Cl is the weighted average of the atomic masses of its isotopes.

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its percent abundance).

Atomic mass of Cl-35 = 17p + 18n = 17 × 1.007 u + 18 × 1.009 u

= 17.119 u + 18.162 u = 35.28 u

Atomic mass of Cl-37 = 17p + 20n = 17 × 1.007 u + 20 × 1.009 u

= 17.119 u + 20.180 u = 37.30 u

Set up a table for easy calculation.

0.755 × 35.28 u =  26.64  u

0.245 × 37.30 u =    9.138 u

             TOTAL = 35.8     u

Note: The actual atomic mass of Cl is 35.45 u.

The calculated value above is incorrect because

(a) the given isotopic percentages are incorrect and

(b) the protons and neutrons have less mass when they are in the nucleus than when they are free. Thus, the calculated masses of Cl-35 and Cl-37 are too high.

7 0
4 years ago
Read 2 more answers
For the reaction of oxygen and nitrogen to form nitric oxide, consider the following thermodynamic data: ΔH∘rxn 180.5 kJ/mol ΔS∘
nasty-shy [4]

Answer:

7.28 × 10³ K

Explanation:

Let's consider the following reaction.

N₂(g) + O₂(g) → 2 NO(g)

The reaction is spontaneous when the standard Gibbs free energy (ΔG°) is negative. ΔG° is related to the standard enthalpy of the reaction (ΔH°) and the standard entropy of the reaction (ΔS°) through the following expression.

ΔG° = ΔH° - T . ΔS°

If ΔG° < 0,

ΔH° - T . ΔS° < 0

ΔH° < T . ΔS°

T > ΔH°/ΔS° = (180.5 × 10³ J/mol)/(24.8 J/mol.K) = 7.28 × 10³ K

The reaction is spontaneous above 7.28 × 10³ K.

7 0
4 years ago
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