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Mariulka [41]
2 years ago
6

Hey there .. Plz help me solve this . ​

Mathematics
1 answer:
Ivahew [28]2 years ago
7 0

Answer:

I don't understand your question!!!

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-17x + 2 +3x^2 + 2x^3 divided by x-2
Stells [14]

Answer:

2x^2+7x-3

remainder is -4

Step-by-step explanation:

Check the image

6 0
3 years ago
The area on a wall covered by a rectangular poster is 270 square inches. The length of the poster is 1.2 times longer than the w
forsale [732]

Answer:

Length = 18 in

Width = 15 in

Step-by-step explanation:

We have that the area of a rectangle is:

A = L * W

but L = 1.2 * W

A = 1.2 * (W ^ 2)

1.2 * (W ^ 2) = 270

(W ^ 2) = 270 / 1.2

W ^ 2 = 225

Therefore, W is equal to:

W = 225 ^ (1/2)

W = +/- 15, but only +15 makes sense

W = 15

Now for L:

L = 1.2 * 15

L = 18

A = 15 * 18 = 270 in ^ 2

4 0
3 years ago
A package weighs 4.25 kilograms. How many grams does the package weigh?(Please Show Work :D)
Bumek [7]
Hello!

4.25 kilograms = C. 4,250 g.


I really hope you found this helpful! :)
6 0
3 years ago
The length of 2 sides on an isosceles triangle is 15. What is the range of possible lengths for the other leg?
erica [24]

Answer:

34

Step-by-step explanation:

4 0
3 years ago
A librarian has 4 identical copies of Hamlet, 3 identical copies of Macbeth, 2 identical copies of Romeo and Juliet, and one cop
lesantik [10]

Answer:

The number of distinct arrangements is <em>12600</em><em>.</em>

Step-by-step explanation:

This is a permutation type of question and therefore the number of distinguishable permutations is:

n!/(n₁! n₂! n₃! ... nₓ!)

where

  • n₁, n₂, n₃ ... is the number of arrangements for each object
  • n is the number of objects
  • nₓ is the number of arrangements for the last object

In this case

  • n₁ is the identical copies of Hamlet
  • n₂ is the identical copies of Macbeth
  • n₃ is the identical copies of Romeo and Juliet
  • nₓ = n₄ is the one copy of Midsummer's Night Dream

Therefore,

<em>Number of distinct arrangements =  10!/(4! × 3! × 2! × 1!)</em>

<em>                                                         = </em><em>12600 ways</em>

<em />

Thus, the number of distinct arrangements is <em>12600</em><em>.</em>

4 0
3 years ago
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