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7nadin3 [17]
3 years ago
10

P=1/2kx^

SAT
1 answer:
Ivan3 years ago
8 0

Answer:

Extension, x = 0.025m

Explanation:

Given the following data;

Spring constant = 25600 N/m

Potential energy = 8 Joules

To find the extension;

Mathematically, the potential energy stored in a spring is given by the formula;

P.E = \frac {1}{2}Kx^{2}

Where;

  • P.E is potential energy.
  • K is the spring constant.
  • x is the extension of the spring.

Substituting into the equation, we have;

8 = \frac {1}{2}*25600*x^{2}

Cross-multiplying, we have;

16 = 25600x^{2}

x^{2} = \frac {16}{25600}

x = \sqrt {0.000625}

<em>Extension, x = 0.025m</em>

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