Answer:
no solution
Step-by-step explanation:
Given
- 3 | 6n - 2 | + 5 = 8 ( subtract 5 from both sides )
- 3 | 6n - 2 | = 3 ( divide both sides by - 3 )
| 6n - 2 | = - 1
The absolute value always returns a positive value and so
| 6n - 2 | ≠ - 1
Hence there is no solution to the equation
Answer:
Step-by-step explanation:
The problem is:
<em>Lola says: Argos, my dog, has 10 kilograms less than Roco. How much kilograms Argos has?</em>
<em />
This problem is about algebraic language. We just need to express the ordinaty language into an equation.
We know the words less means difference. So, let's call 
Argos' weight and 
Roco's weight. We can expresse the given problem as
Notice that we applied a difference due to the word "less" in the problem.
Therefore, Argo's weight is given by the expression
Answer:
-1000
Step-by-step explanation:
1. Do the Parenthesis problem first. (PEDMAS/PEMDAS)
You should then have -10^3
2. Solve with the exponent. (-10 x 10 x 10)
You should then get your final answer, which is -1000.
Any Questions/Concerns?
Answer:
u = -5/9
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
-3(u + 2) = 5u - 1 + 5(2u + 1)
<u>Step 2: Solve for </u><em><u>u</u></em>
- Distribute: -3u - 6 = 5u - 1 + 10u + 5
- Combine like terms: -3u - 6 = 15u + 4
- Add 3u to both sides: -6 = 18u + 4
- Subtract 4 on both sides: -10 = 18u
- Divide 18 on both sides: -10/18 = u
- Simplify: -5/9 = u
- Rewrite: u = -5/9
<u>Step 3: Check</u>
<em>Plug in u into the original equation to verify it's a solution.</em>
- Substitute in <em>u</em>: -3(-5/9 + 2) = 5(-5/9) - 1 + 5(2(-5/9) + 1)
- Multiply: -3(-5/9 + 2) = -25/9 - 1 + 5(-10/9 + 1)
- Add: -3(13/9) = -25/9 - 1 + 5(-1/9)
- Multiply: -13/3 = -25/9 - 1 - 5/9
- Subtract: -13/3 = -34/9 - 5/9
- Subtract: -13/3 = -13/3
Here we see that -13/3 does indeed equal -13/3.
∴ u = -5/9 is a solution of the equation.
9514 1404 393
Answer:
100°
Step-by-step explanation:
Arc BC is twice the measure of inscribed angle BEC, so is ...
arc BC = 2×50°
arc BC = 100°
