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lyudmila [28]
3 years ago
5

Can someone help with all of these

Mathematics
1 answer:
Reil [10]3 years ago
7 0

Answer:

False

True

True

False

Step-by-step explanation:

90/5 = 18 x 8 = 144 jars of paint

90/3 = 30 x 10 = 300 sketch pads

300:144 = 25:12

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(d) A car travels at an average speed of 80 km/h. How far does it travel in: (1) 2 hours? (11) 12 minutes?​
zepelin [54]
Answer is (1) 160 km in 2 hours and
(2) 16 miles in 12 minutes.

Step by step.
80 km / 1 hour = x km /2 hours
Cross multiply =
x = 160

The second one requires a little more math. Because we are looking at how far in minutes, we change the rate of 80km in 1 hour to 80 km in 60 minutes.
80 km / 60 = x / 12
Cross multiply
12x = 960
Solve for x by dividing both sides by 12
X = 16

I did the math on a print screen to explain the cross multiply.

3 0
2 years ago
A lidless box is to be made using 2m^2 of cardboard find the dimensions of the box that requires the least amount of cardboard
Jlenok [28]
1.8, Problem 37: A lidless cardboard box is to be made with a volume of 4 m3 . Find the dimensions of the box that requires the least amount of cardboard. Solution: If the dimensions of our box are x, y, and z, then we’re seeking to minimize A(x, y, z) = xy + 2xz + 2yz subject to the constraint that xyz = 4. Our first step is to make the first function a function of just 2 variables. From xyz = 4, we see z = 4/xy, and if we substitute this into A(x, y, z), we obtain a new function A(x, y) = xy + 8/y + 8/x. Since we’re optimizing something, we want to calculate the critical points, which occur when Ax = Ay = 0 or either Ax or Ay is undefined. If Ax or Ay is undefined, then x = 0 or y = 0, which means xyz = 4 can’t hold. So, we calculate when Ax = 0 = Ay. Ax = y − 8/x2 = 0 and Ay = x − 8/y2 = 0. From these, we obtain x 2y = 8 = xy2 . This forces x = y = 2, which forces z = 1. Calculating second derivatives and applying the second derivative test, we see that (x, y) = (2, 2) is a local minimum for A(x, y). To show it’s an absolute minimum, first notice that A(x, y) is defined for all choices of x and y that are positive (if x and y are arbitrarily large, you can still make z REALLY small so that xyz = 4 still). Therefore, the domain is NOT a closed and bounded region (it’s neither closed nor bounded), so you can’t apply the Extreme Value Theorem. However, you can salvage something: observe what happens to A(x, y) as x → 0, as y → 0, as x → ∞, and y → ∞. In each of these cases, at least one of the variables must go to ∞, meaning that A(x, y) goes to ∞. Thus, moving away from (2, 2) forces A(x, y) to increase, and so (2, 2) is an absolute minimum for A(x, y).
5 0
4 years ago
Find the LCM and HCF of 110 and 220 by prime factorization what do you observe....pls answer this ​
ElenaW [278]

Answer: Check if numbers are prime. Composite numbers prime factorization (decomposing, breaking numbers down to prime factors). Inscribe them as a product of prime factors, in exponential notation.

8 0
3 years ago
ANYONE...........help​
KATRIN_1 [288]

Answer:

  • 1 cm

Step-by-step explanation:

<u>Sides of the picture added margin:</u>

  • l = 8 + 2x
  • w = 5 + 2x
  • A(margin) = 30 cm²

<u>Solution</u>:

  • A(margin) = Total area - A(picture)
  • (8 + 2x)(5 + 2x) - 5*8 = 30
  • 4x² + 10x + 16x + 40 - 40 - 30 = 0
  • 4x² + 26x - 30 = 0
  • 2x² + 13x - 15 = 0
  • x = (-13 + √(13² + 2*4*15))/4
  • x = (-13 + 17)/4
  • x = 1 cm

Note. The other root is ignored as negative.

3 0
3 years ago
Samantha needs 4/5 yard of fabric to make costumes for the school play. Write and solve and equation to find how many costumes s
ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

Samantha needs 4/5 yard of fabric to make costumes for the school play.

Let x represent the number of yards of fabric that she has

Let y represent the total number of costumes that she can make from x yards of fabric.

Since one costume require 4/5 yards of fabric, y costumes will require

x ÷ 4/5 = x×5/4 = 5x/4

The equation will be

y = 5x/4

to find how many costumes she can make with 8 yards of fabric, it becomes

y = (5×8)/4

y = 40/4 = 10

5 0
3 years ago
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