Ask question

Ask question

All categories

Elena-2011 [213]

3 years ago

6

Which of the following can be used to prove two lines crossed by a transversal are parallel? Question 11 options: Congruent Alte

rnate Interior Angles Congruent Corresponding Angles Supplementary Same-Side Exterior Angles All of the above None of the above

1 answer:

beks73 [17]3 years ago

3 0

Supplementary angles

You might be interested in

Select all the pairs that are<br> equivalent. Someone please help me. The question is number 2

ycow [4]

the answer is in the picture

8 0

3 years ago

A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard

Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

$\sigma=\frac{0.8}{\sqrt{37}}=0.13$

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

$z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69$

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, $P(z > 1.69) = 1 - P(z < 1.69)$

$P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%$

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0

3 years ago

The question is in the picture.

nordsb [41]

The first bullet is the answer

7 0

3 years ago

Which is not a true statement about the transformation below

hjlf

Step-by-step explanation:

<em>option</em><em> </em><em>D </em><em>is </em><em>correct</em><em>,</em>

<em>because</em><em> </em><em>the </em><em>orientation</em><em>/</em><em>postion</em><em> </em><em>of </em><em>the </em><em>vertices </em><em>does </em><em>got </em><em>changed.</em><em>.</em><em>.</em>

<em>that's</em><em> </em><em>why </em><em>it </em><em>is </em><em>not </em><em>true</em>

<em>hope </em><em>this </em><em>answer </em><em>helps </em><em>you </em><em>dear </em><em>take</em><em> </em><em>care</em>

3 0

3 years ago

Determine whether the series is convergent or divergent.

elixir [45]

Answer:

Step-by-step explanation:

Test for convergence or divergence of a series using Comparison test

Function.

Σ Sin(1/n). From n= 1 to n=∞

Comparison test states that

Let, 0 ≤ an ≤ bn

For all n

Then, if

Σbn converges then, Σan converge

Σan diverges then, Σbn diverge

I.e if the small series diverges, then, the big series diverges and if the big series converges then, the small series converges.

Let compare the given function to 1/n

1/n is greater than Sin(1/n)

0 ≤ Sin(1/n) ≤ 1/n

1/n is a positive number and it is always greater than 1.

We know that 1/n diverse from p series

P series says that,

Σ 1/n^p

If p≤1 then the series diverges

If p>1 the series converges

So when we compare this to 1/n, then p is equal to 1, therefore, the series diverges.

Now, comparing this to the comparison thereom

Since, the large series bn diverges, then the smaller series an diverges.

Then,

Σ 1 / n diverges implies that.

Σ Sin(1/n) diverges too

5 0

3 years ago