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ahrayia [7]
3 years ago
7

Will give brainleist

Mathematics
2 answers:
Mama L [17]3 years ago
4 0

Answer:

A

Step-by-step explanation:

sasho [114]3 years ago
3 0

Answer:

Step-by-step explanation:

The deposits helped them produce iron goods.

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"A country has 50 million people, 30 million of whom are adults. Of the adults, 5 million are not interested in working, another
Pani-rosa [81]

Answer:

There are 20 million people in the labour force.

Step-by-step explanation:

There are 50 million people in the country.

30 million people are adults.

Out of the 30 million, 5 million are not interested in working. Assuming every adult does what he/she wants, then these 5 million are not working. The list then reduces to

30 - 5 = 25 million.

Another 5 million are interested in working but have given up looking for work. The list reduces to

25 - 5 = 20 million.

5 million people are working part time but would like to work full time. They are working, it doesn't matter if it is part time or full time, they are in the labour force.

10 million people are working full time. They are also in the labour force.

THERE ARE 20 MILLION PEOOLE IN THE LABOUR FORCE

3 0
4 years ago
At a football game, 92% of people attending were supporting the home team, while 8% were supporting the visiting team. If the to
Harlamova29_29 [7]

Answer:

552 supporters of the home team.

Step-by-step explanation:

92% × 600 = 552

4 0
3 years ago
Find the exact value of cos(theta) for an angle (theta) with tan (theta)= -2/3 and with its terminal side in Quadrant II.
Naya [18.7K]

Answer:

-\frac{3\sqrt{13}}{13}.

Step-by-step explanation:

Since we are in quadrant two, cosine value is negative while sine value is positive.

We are going to use the Pythagorean Identity: 1+\tan^2(\theta)=\sec^2(\theta).

1+(\frac{-2}{3})^2=\sec^2(\theta)

1+\frac{4}{9}=\sec^2(\theta)

\frac{9+4}{9}=\sec^2(\theta)

\frac{13}{9}=\sec^2(\theta)

\pm \sqrt{\frac{13}{9}}=\sec(\theta)

\pm \frac{\sqrt{13}}{3}=\sec(\theta)

Since cosine and secant are reciprocals then they will have the same sign as along as they both exist.

\sec(\theta)=-\frac{\sqrt{13}}{3}

\cos(\theta)=-\frac{3}{\sqrt{13}}.

I don't see this answer as I'm going to rationalize the denominator.

\cos(\theta)=-\frac{3}{\sqrt{13}} \cdot \frac{\sqrt{13}}{\sqrt{13}}.

\cos(\theta)=-\frac{3\sqrt{13}}{13}.

8 0
4 years ago
Read 2 more answers
. 14 - (-10) 4 -4 24 -24
Dennis_Churaev [7]

Answer:

24

Step-by-step explanation:

14 - (-10)

A negative negative is a postive

14 + 10

24

7 0
3 years ago
What is the inverse of y=cos(x-pi/2)​?
alekssr [168]

Answer:

f − 1 ( x ) = arccos  ( x ) +  π/ 2

Step-by-step explanation:

y=cos(x-pi/2)

For inverse, interchange the variables and solve for y

f − 1 ( x ) = arccos  ( x ) +  π/ 2

6 0
3 years ago
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