You did it wrong it. It should be facing right with an open circle
x° = 43°
Solution:
The lines AD, BE and CF are intersecting lines.
Given m∠AGF = 47°, m∠BGC = 90°, m∠DGE = x°.
To find the value of x°:
Line BE and line CF intersect at the vertex G.
∠BGC and ∠FGE are vertical angles.
<u>Vertical angle theorem:</u>
If two angles are vertically opposite then they are congruent.
By vertical angle theorem, ∠BGC ≅ ∠FGE
⇒ m∠FGE = 90°
Sum of the angles in a straight line = 180°
In line AD,
m∠AGF + m∠FGE + m∠DGE = 180°
⇒ 47° + 90° + m∠DGE = 180°
⇒ 137° + m∠DGE = 180°
⇒ m∠DGE = 180° – 137°
⇒ m∠DGE = 43°
⇒ x° = 43°
Hence the value of x° is 43°.
220c-287=103
add 287 to both sides
220c=390
divide both sides by 220
c=1.77
Answer:
Answer in terms of π=144π m^3
Answer by replacing π with 3.14 is 452.16 approximately 452.2m^3
Answer to the nearest whole no. is 452m^3
Step-by-step explanation:
We are given the equation:
h = 22,000 – 480 t
where h is height . The plane will land when h = 0,
therefore:
0 = 22,000 – 480 t
480 t = 22,000
t = 45.83 minutes
<span>hence the plane will land after 45.83 minutes</span>