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Harlamova29_29 [7]
3 years ago
6

I need help anyoneeeeeee

Mathematics
1 answer:
pshichka [43]3 years ago
8 0

Answer:

answer is 1004.8 cubic feet

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An expression is shown. -8+4-7-9-2+(-5) What is the value of the expression? ​
Colt1911 [192]

Answer:

-27

Step-by-step explanation:

-8+4-7-9-2+(-5)

= -4-7-9-2-5

= -20-2-5

= -27

4 0
3 years ago
Julio is paid 1.4 times his normal hourly rate for each hour he works over 30 hours in a week. Last week he worked 35 hours and
patriot [66]
N = regular rate
1.4n= overtime rate

30n + 5(1.4n) = $436.60  (30 hours x regular rate n)  plus 5 hours at 1.4 times reg rate.

30n + 7n = $436.60    now add like terms
37n = $436.60    now divide both sides by 37
n= $11.80   
Check to see if my answer is reasonable 30 x 12= 360  + 5 x 10 x 1.4 = about 70 (notice that I used 10 instead of 12 here so I could do it in my head)
360 + 70 = 430 - close enough - my answer is reasonable
Check:
(30 x $11.80) + 5 ( 1.4 x 11.80
354 + 5( 16.52)
354 + 82.60 = 436.60    ($436.60)
6 0
3 years ago
Read 2 more answers
Solve the following equation:
stealth61 [152]

Answer: Y=1/8

Slope m=0, b =1/8

Step-by-step explanation:

8 0
2 years ago
What is the volume of a sphere that has a diameter of 18 in.?
True [87]
The formula is 4/3 times pi times radius cubed. The radius is 9. 4/3 is 1.33. 3.14 times 9 cubed is 81 times 3.14. That is 254.34. 1.33 times 254.34 is 338.2722. That rounds to 338.
6 0
2 years ago
Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u > 0.
max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

4 0
2 years ago
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