Answer:
y=-3/4x+5.5
Step-by-step explanation:
You just need to try with all of the pair f.ex
0,-2 -> put 0 in the x-> y=8*0-2=-2 so ok it is q possible pair of the function..
You try every pair till you find set where all the pairs fit
So set 1
1 and 6: 8*1-2=6 ok
2 and 14 : 8*2-2=14 ok
Hope I could help
Answer:
D
Step-by-step explanation:
our basic Pythagorean identity is cos²(x) + sin²(x) = 1
we can derive the 2 other using the listed above.
1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)
1 + tan²(x) = sec²(x)
2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)
cot²(x) + 1 = csc²(x)
A. sin^2 theta -1= cos^2 theta
this is false
cos²(x) + sin²(x) = 1
isolating cos²(x)
cos²(x) = 1-sin²(x), not equal to sin²(x)-1
B. Sec^2 theta-tan^2 theta= -1
1 + tan²(x) = sec²(x)
sec²(x)-tan(x) = 1, not -1
false
C. -cos^2 theta-1= sin^2
cos²(x) + sin²(x) = 1
sin²(x) = 1-cos²(x), our 1 is positive not negative, so false
D. Cot^2 theta - csc^2 theta=-1
cot²(x) + 1 = csc²(x)
isolating 1
1 = csc²(x) - cot²(x)
multiplying both sides by -1
-1 = cot²(x) - csc²(x)
TRUE
Answer:
The correct answer is - 768.
Step-by-step explanation:
The given question is based on a specific pattern present in between the numbers in the given series -
Series = 25 50 99 196 388
to find - next number in series
let us find the relation between the initial two number:
25 - 50, here number 50 is two times of 25 or (x*2-0)
relation between 2nd and 3rd number:
50 - 99, here 99 is two times of 50 minus 1 or (x*2-1)
relation between 3rd and 4th number:
99 - 196, here 196 is two times of 99 minus 2 or (x*2-2)
relation between 4th and 5th number:
196 - 388, here 388 is the two times of 196 minus 4 or (x*2-4)
So on this pattern, the next number would be = x*2-8
388*2-8
= 768
