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frozen [14]
2 years ago
11

How do you solve ? 2(x−(3+2x)+9)=3x−8

Mathematics
1 answer:
PIT_PIT [208]2 years ago
6 0

Hey there!!

Given equation :

... 2 ( x - ( 3 + 2x ) + 9 ) = 3x - 8

Using the distributive property.

... 2 ( x - 3 - 2x + 9 ) = 3x - 8

... 2 ( -x + 6 ) = 3x - 8

Using the distributive property.

... -2x + 12 = 3x - 8

Subtracting 12 on both sides.

... -2x = 3x - 8 - 12

... -2x = 3x - 20

Subtracting 3x on both sides.

... -2x - 3x = -20

... -5x = -20

Dividing by -5 on both sides.

... x = -20 / -5

... x = 4

<em>Hence, the answer is 4. </em>

Hope my answer helps!

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Answer:

-  \frac{5}{6}

Step-by-step explanation:

The first thing to do is solve for the root. A trick is to ignore the numerator and only focus on the denominator in the root. So it is a third root so you have to find out what multiplied by itself three times is 343. The correct answer for that is 7. So now we must introduce the numerator back, so it would be:

\frac{1}{7}

I'll show the new expression below.

\frac{1}{6}  - 7( \frac{1}{7} )

Second order of business is to multiply the second half of the expression. Easy enough the 7 cancels out the 1/7. New expression below.

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5 0
2 years ago
Read 2 more answers
What is the solution to the inequality -8x + 4 &lt; -4?
never [62]

Answer:

x > 1

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

-8x + 4 < -4

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Subtract 4 on both sides:                    -8x < -8
  2. Divide -8 on both sides:                       x > 1

Here we see that any value <em>x</em> greater than 1 would work as a solution.

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2 years ago
37. The students at Norton School were asked to name their favorite type of
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Answer: 60 students

Step-by-step explanation:

So, in the first situation 430 students were surveyed and 258 said that their favourite pet was a dog. The second situation is 100 students and x said that their favourite pet was a dog. We are solving x.

430=258

100= x

Cross multiply

So that is

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Divide both sides by 430

Answer: 60 students

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3 years ago
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\bf \begin{cases} x^2+y^2=400\\ \boxed{y}=x-28 \end{cases}\qquad \stackrel{\textit{substituting on the 1st equation}}{x^2+\left( \boxed{x-28} \right)^2=400} \\\\\\ x^2+(x^2-56x+28^2)=400\implies x^2+x^2-56x+28^2=400 \\\\\\ 2x^2-56x+784=400\implies 2x^2-56x+384=0 \\\\\\ 2(x^2-28x+192)=0\implies x^2-28x+192=0 \\\\\\ (x-16)(x-12)=0\implies x = \begin{cases} 16\\ 12 \end{cases}

now that we know what are the x-values, what are the y-values? well, we can just use the 2nd equation, since we know that y = x - 28, then

\bf y = x - 28\implies \stackrel{\textit{when x = 16}}{y = 16 - 28}\implies y = -12 \\\\\\ y = x - 28\implies \stackrel{\textit{when x = 12}}{y = 12 - 28}\implies y = -16 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (\stackrel{x}{16}~~,~~\stackrel{y}{-12})\qquad,\qquad (\stackrel{x}{12}~~,~~\stackrel{y}{-16})~\hfill

7 0
2 years ago
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