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r-ruslan [8.4K]
3 years ago
10

Someone help i need this pretty quick

Mathematics
1 answer:
KIM [24]3 years ago
8 0
Gotchu - t= 15.1

DISTRIBUTE AND SIMPLIFY
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In the function f (x) = = (x²-1) / (x-1), what happens if x takes the value of 1? Explain your answer.
zhenek [66]

Answer:

If x=1, then f(x)= undefined

Step-by-step explanation:

1*1=1

1-1=0

0/0

You can't divide by 0, so anything that is divided by 0 is undefined.

((1*1)-1)/(1-1)

(1-1)/(1-1)

0/0

0/0=Undefined

f(x)= undefined

6 0
3 years ago
Solve for ddd. 6d-\dfrac{11}2=2d-\dfrac{13}26d− 2 11 ​ =2d− 2 13 ​ 6, d, minus, start fraction, 11, divided by, 2, end fraction,
ANEK [815]

Answer:

d = -\dfrac{1}{4}

Step-by-step explanation:

Given

6d-\dfrac{11}2=2d-\dfrac{13}{2}

Required

Solve for d

6d-\dfrac{11}2=2d-\dfrac{13}{2}

Collect Like Terms

-2d + 6d=-\dfrac{13}{2}+\dfrac{11}{2}

4d=-\dfrac{13}{2}+\dfrac{11}{2}

Take LCM

4d=\dfrac{-13+11}{2}

4d=\dfrac{-2}{2}

4d = -1

Make d the subject

d = -\dfrac{1}{4}

5 0
3 years ago
Solve the following equation for x. x = -2 x = 2 x = -17 x = -7 (x - 5)/2 = -6
nordsb [41]

Step-by-step explanation:

x= -2,

(x - 5) / 2= -6

( (-2) - 5) / 2= -6

(-7) / 2 = -6

-3.5 = - 6

right hand side not equal to left hand side of this equation.so,x= -2 cannot exist for this equation.

x=2,

(x - 5) / 2= -6

(2 - 5) / 2= -6

(-3) / 2= -6

-1.5 = - 6

right hand side not equal to left hand side of this equation.so,x= 2 cannot exist for this equation.

x= -17

(x - 5) / 2= -6

( ( -17) - 5) / 2= -6

(- 22) / 2= -6

-11 = -6

right hand side not equal to left hand side of this equation.so,x= -17 cannot exist for this equation.

x= -7,

(x - 5) / 2= -6

( ( -7) -5) / 2= -6

(-12) / 2= -6

-6= -6

right hand side equal to left hand side of this equation.so,x= -7 exist for this equation.

8 0
3 years ago
Line segment ab has a length of 4 units. it is translated 1 unit to the right on a coordinate plane to obtain line segment a pri
earnstyle [38]
The answer is B 4. tell me if it is right to be marked brailyist
5 0
4 years ago
Read 2 more answers
Help pls i dont understand how to do this :')
andriy [413]

Answer:

7/8

Step-by-step explanation:

Use the Pythagorean Identity

( \sin(x) ) {}^{2}  + ( \cos(x) ) {}^{2}  = 1

Plug in

\frac{ \sqrt{15} }{8}

for cos x.

(\sin(x) ) {}^{2}  + ( \frac{ \sqrt{15} }{8} ) {}^{2}  = 1

( \sin(x) ) {}^{2}  +  \frac{15}{64}  = 1

( \sin(x) ) {}^{2}  =  \frac{49}{64}

\sin(x)  =  \frac{7}{8}

3 0
2 years ago
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