1)
I:x-y=-7
II:x+y=7
add both equations together to eliminate y:
x-y+(x+y)=-7+7
2x=0
x=0
insert x=0 into II:
0+y=7
y=7
the solution is (0,7)
2)
I: 3x+y=4
II: 2x+y=5
add I+(-1*II) together to eliminate y:
3x+y+(-2x-y)=4+(-5)
x=-1
insert x=-1 into I:
3*-1+y=4
y=7
the solution is (-1,7)
3)
I: 2e-3f=-9
II: e+3f=18
add both equations together to eliminate f:
2e-3f+(e+3f)=-9+18
3e=9
e=3
insert e=3 into I:
2*3-3f=-9
-3f=-9-6
-3f=-15
3f=15
f=5
the solution is (3,5)
4)
I: 3d-e=7
II: d+e=5
add both equations together to eliminate e:
3d-e+(d+e)=7+5
4d=12
d=3
insert d=3 into II:
3+e=5
e=2
the solution is (3,2)
5)
I: 8x+y=14
II: 3x+y=4
add I+(-1*II) together to eliminate y
8x+y+(-3x-y)=14-4
5x=10
x=2
insert x=2 into II:
3*2+y=4
y=4-6
y=-2
the solution is (2,-2)
A cause she measured the side of it
EDITED:
so lets make the question more clear
lets make it like this, if were gonna make 10 = b vv (sorry I meant to say 10, but I said 6 ;-;
3(10) - 4 + 6(10-9) = 30 - 4 + 6 = 26 + 6 = 32
= THIS EQUALS 32
Now lets do 9(b-6) - 4 which will be turned into 9(10-6) - 4 = 36 - 4 = THIS EQUALS 32
MY ANSWER IS YES (DONT ASK ME WHY IM WRITING IN CAPS (((: )
Answer: 2.663043987
explanation: use calculator
Answer:
Step-by-step explanation:
we know that
The circumference of a circle is equal to
in this problem
substitute
-----> exact value of the circumference
Find the approximate value of the circumference
assume
