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2 years ago

1.

Mathematics

1 answer:

Basile [38]2 years ago

5 0

Answer: x^20

Step-by-step explanation:

We can easily solve this question by using a graphing calculator and plotting each of the graphs.

We know that

* ln(x) grows the slowest for a given input of x

* sin(x) is a periodic function with values between [-1,1]

*Exponentials grow faster than the rest of the functions, so

x^20 grows the fastest as x goes to infinity

Step-by-step explanation:

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Anyone know how to do these and explain so I can do the rest lol.

klasskru [66]

Answer:

Option B. m⁷/n² is the correct answer.

Step-by-step explanation:

Identity,

xᵃ * xᵇ = xᵃ⁺ᵇ

xᵃ/xᵇ = xᵃ⁻ᵇ

x⁻ᵃ = 1/xᵃ

It is given that,

m⁻⁶ n⁻³/m⁻¹³ n⁻¹

Using these three identities we can write,

m⁻⁶ n⁻³/m⁻¹³ n⁻¹ = m⁻⁶ m¹³/n⁻¹n³ (since x⁻ᵃ = 1/xᵃ)

m⁻⁶ m¹³/n⁻¹n³ =m⁽⁻⁶⁺¹³⁾/n⁽⁻¹⁺³⁾ = m⁷/n² (since xᵃ * xᵇ = xᵃ⁺ᵇ and xᵃ/xᵇ = xᵃ⁻ᵇ)

Therefore Option B. m⁷/n² is the correct answer

6 0

2 years ago

Read 2 more answers

A triangle has three sides 35cm 54 cm and 61 cm find its area Also find the smallest of its altitude

I am Lyosha [343]

Answer:

Area of given triangle is 939.15cm² and smallest altitude is 30.8cm

<h3>Solution:</h3>

We are given three sides of a triangle, Let the sides be :

( a ) = 35 cm

( b ) = 54 cm

( c ) = 61 cm

We can find the area of the triangle with its three sides using Heron's Formula

Heron's Formula

Heron's formula was founded by hero of Alexandria, for finding the area of triangle in terms of the length of its sides. Heron's formula can be written as:

$\sf{ \pmb { \longrightarrow \: \sqrt{s(s - a)(s - b)(s - c)} }}$

where ( s ) :

$\sf \longrightarrow s = \dfrac{a + b + c}{2}$

Therefore, for the given triangle first we will calculate ( s )

$\begin {aligned}\quad & \quad \longmapsto \sf s = \dfrac{a + b + c}{2} \\ & \quad \longmapsto \sf s = \dfrac{35 + 54 + 61}{2} \\ & \quad \longmapsto \sf s = \dfrac{150}{2} \\ & \quad \longmapsto \sf s = 75cm \end{aligned}$

Now, Area of triangle will be:

$\begin{aligned}&:\implies \sf\quad \sf \: A = \sqrt{s(s - a)(s - b)(s - c)} \\ &:\implies \sf\quad \sf \: A = \sqrt{75(75 - 35)(75 - 54)(75 - 61)} \\&:\implies \sf\quad \sf \: A = \sqrt{75 \times 40 \times 21 \times 14} \\ &:\implies \sf\quad \sf \: A = \sqrt{5 \times 5 \times 3 \times 3 \times 2 \times 2 \times 7 \times 7 \times 2 \times 2 \times 5} \\ &:\implies \sf\quad \sf \: A =5 \times 3 \times 2 \times 7 \times 2 \sqrt{5} \\ &:\implies \sf\quad \sf \: A =420 \times 2.23 \\ &:\implies \sf\quad \sf \boxed{ \pmb{ \sf A =939.15 {cm}^{2} }} \end{aligned}$

Also, we have to find the smallest altitude, and the smallest altitude will be on the longest side. So,

$\begin{aligned}&:\implies \sf\quad \sf \: Area =939.15 \\ &:\implies \sf\quad \sf \: \dfrac{1}{2} \times b \times h =939.15 \\ &:\implies \sf\quad \sf \: \dfrac{1}{2} \times 61 \times h = 939.15 \\&:\implies \sf\quad \sf \: h =939.15 \times \dfrac{2}{61} \\&:\implies \sf\quad \sf \: h = \dfrac{1818.3}{61} \\ &:\implies \sf\quad \boxed{ \pmb{\sf \: h =30.79 \: (approx)}} \end{aligned}$