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QveST [7]
3 years ago
7

graph the parabola y equals negative x squared + 3 to graph a parabola plot the vertex and four additional points two on each si

de of the vertex then click on the graph icon
Mathematics
1 answer:
Nataliya [291]3 years ago
6 0

You don't have the graph icon here, so we'll have to graph this parabola without it.


Your parabola is y = -x^2 + 3., which resembles y = a(x-h)^2 + k. We can tell immediately that this parabola opens down and that the vertex is (0,3).


Plot (0,3). Besides being the vertex, this point is also the max. of the function.


Now calculate four more points. Choose four arbitrary x-values, such as {-2, 1, 4, 5} and find the y value for each one. Plot the resulting four points. Draw a smooth curve thru them, remembering (again) that the vertex is at (0,3) and that the parabola opens down.

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300 feet

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A triangle has sides of lengths 8, 15, and 17. Is it a right triangle? Explain.
natta225 [31]

Answer:

Step-by-step explanation:

8^2 + 15^2 = ?

64 + 225 = 17^2

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Which equation represents a line which is parallel to the line x+4y=-20x+4y=−20?
g100num [7]

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y=7x+3, y=7x−6

7 0
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The volume of the prism shown in 60 cm Given the dimensions shown below, what would be the value of x ?
hodyreva [135]

Answer:

(3× - 2)(x - 1)

3x² - 3x - 2× -2

3x² - 5× - 2

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8 0
3 years ago
Find the distance between the points (0, 0) and (6, -8). 4 √28 10
kvasek [131]

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10

Step-by-step explanation:

The formula for finding the distance between 2 points (x1, y1) and (x2, y2) is

d = √[(x2 - x1)² + (y2 - y1)²]

Here (x2, y2) = (6, -8)  and (x1, y1) = (0, 0)

Plugging them gives us

d = √[(6 - 0)² + (-8 - 0)²]

     d = √[(6)² + (-8)²]

        d = √[36 + 64]

           d = √100

               d = 10

6 0
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