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QveST [7]
2 years ago
7

graph the parabola y equals negative x squared + 3 to graph a parabola plot the vertex and four additional points two on each si

de of the vertex then click on the graph icon
Mathematics
1 answer:
Nataliya [291]2 years ago
6 0

You don't have the graph icon here, so we'll have to graph this parabola without it.


Your parabola is y = -x^2 + 3., which resembles y = a(x-h)^2 + k. We can tell immediately that this parabola opens down and that the vertex is (0,3).


Plot (0,3). Besides being the vertex, this point is also the max. of the function.


Now calculate four more points. Choose four arbitrary x-values, such as {-2, 1, 4, 5} and find the y value for each one. Plot the resulting four points. Draw a smooth curve thru them, remembering (again) that the vertex is at (0,3) and that the parabola opens down.

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A box is x to inches high,(2x+3)inches wide, and (2x+5) of inches long. In terms of x, what is the volume (v) of the box?
Advocard [28]

Answer:

The volume of the box is V=(4x^3+16x^2+15x)\ in^3

Step-by-step explanation:

we know that

The volume of the box is equal to

V=LWH

where

L is the length of the box in inches

W is the width of the box in inches

H is the height of the box in inches

we have

L=(2x+5)\ in\\W=(2x+3)\ in\\H=x\ in

substitute in the formula

V=(2x+5)(2x+3)x

V=(4x^2+6x+10x+15)(x)

V=(4x^2+16x+15)(x)

V=(4x^3+16x^2+15x)\ in^3

6 0
3 years ago
PLEASE HELP!!! Number 2, and 4 please!! (YOU HAVE TO FIND THE SURFACE AREA OF THE PRISM)
Elenna [48]

The answer for 2 is 192. The answer for 4 is 672.

8 0
3 years ago
Ugh someone help me what is h
saw5 [17]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ h = 2 1/2

Divide the area by the base to get the height.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

8 0
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Given the following information, find the length of the missing side. Leave your answer as a simplified radical.
andreev551 [17]

Answer:

2√3

Step-by-step explanation:

Given the following information,

Long = 3 = Adjacent

Angle of elevation =30 degrees

Required

Hypotenuse

Using SOH CAH TOA identity

Cos theta = adj/hyp

Cos 30 = 3/hyp

hyp = 3/cos30

hyp = 3/√3/2

hyp = 3* 2/√3

hyp = 6/√3

hyp = 6/√3 * √3/√3

hyp = 6√3/3

hyp = 2√3

Hence the hypotenuse is 2√3

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IRINA_888 [86]

Step-by-step explanation:

solution shown in picture

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