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PIT_PIT [208]
3 years ago
15

I am currently struggling on number 5

Mathematics
1 answer:
adoni [48]3 years ago
7 0

Answer:

7 and 5 also 3 probably I guess

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❌❌EVALUATE SQUARE ROOTS❌❌
Oksana_A [137]
The first answer is A then the next answer is C
3 0
3 years ago
Using the attached link below.
Serhud [2]

\text{Use the Pythagorean theorem:}\\\\r-hypotenuse\\\\r^2=7^2+5^2\\\\r^2=49+25\\\\r^2=74\to r=\sqrt{74}

\sin=\dfrac{opposite}{hypotenuse}\\\\\cos=\dfrac{adjacent}{hypotenuse}\\\\\tan=\dfrac{opposite}{adjacent}\\\\\cot=\dfrac{adjacent}{opposite}\\\\\text{We have}\\\\for\ the\ angle\ y:\\\text{opposite = 7}\\\text{adjacent = 5}\\\text{hypotenuse = }\ \sqrt{74}\\\\for\ the\ angle\ x:\\\text{opposite = 5}\\\text{adjacent = 7}\\\text{hypotenuse = }\ \sqrt{74}

\csc x=\dfrac{1}{\sin x}\\\\\sec x=\dfrac{1}{\cos x}

A.\\\\\sin x=\dfrac{5}{\sqrt{74}}=\dfrac{5\sqrt{74}}{74}\\\\\csc y=\dfrac{1}{\frac{7}{\sqrt{74}}}=\dfrac{\sqrt{74}}{7}\\\\B.\\\\\tan x=\dfrac{5}{7}\\\\\cot y=\dfrc{5}{7}\\\\C.\\\\\cos x=\dfrac{7}{\sqrt{74}}=\dfrac{7\sqrt{74}}{7}\\\\\sec y=\dfrac{1}{\frac{5}{\sqrt{74}}}=\dfrac{\sqrt{74}}{5}

D.\\\sin\theta=\dfrac{2}{3}\\\\\sin^2\theta+\cos^2\theta=1\to\left(\dfrac{2}{3}\right)^2+\cos^2\theta=1\\\\\dfrac{4}{9}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{4}{9}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{5}{9}\to\cos\theta=\sqrt{\dfrac{5}{9}}\to\cos\theta=\dfrac{\sqrt5}{3}\\\\\tan\theta=\dfrac{\sin\theta}{\cos\theta}\to\tan\theta=\dfrac{\frac{2}{3}}{\frac{\sqrt5}{3}}=\dfrac{2}{3}\cdot\dfrac{3}{\sqrt5}=\dfrac{2}{\sqrt5}=\dfrac{3\sqrt5}{5}

6 0
3 years ago
The probability is? Please help
ehidna [41]
The sum of the probabilities in a probability distribution is always 1.
A probability distribution is a collection of probabilities that defines the likelihood of observing all of the various outcomes of an event or experiment. Based on this definition, a probability distribution has two important properties that are always true:
Each probability in the distribution must be of a value between 0 and 1.
The sum of all the probabilities in the distribution must be equal to 1.
An example: You could define a probability distribution for the observation for the number displayed by a single roll of a die. The probability that the die with show a "1" is
1
6
.
That's because there are six possible outcomes, and only one of those outcomes is a "1". Lets label the probabilities of all the possible outcomes for the single die.
Roll a "1": Probability is
1
6

Roll a "2": Probability is
1
6

Roll a "3": Probability is
1
6

Roll a "4": Probability is
1
6

Roll a "5": Probability is
1
6

Roll a "6": Probability is
1
6
Each probability is between 0 and 1, so the first property of a probability distribution holds true. And the sum of all the probabilities:
1
6
+
1
6
+
1
6
+
1
6
+
1
6
+
1
6
=
1
,
so the second property of a probability distribution holds true.
3 0
3 years ago
A. Crosses the x-axis two points
NARA [144]
D-does not cross the X axis. It ends at 6 above the X axis
7 0
4 years ago
Use the quadratic formula to solve for x.
Finger [1]
Answer should be if not sorry
X= 1-5/6
7 0
2 years ago
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