What is the rate of change of the cost with respect to the number of miles for the Yellow Cab Company?
1 answer:
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Let us denote the number of tiles by 
.
In the first store, if Darin bought tiles, he would need to spend:
(measured in $)
In the second store, if Darin bought tiles, he would need to spend:
(measured in $)
For the cost to be the same at both stores, it means (measured in $)
Moving
over to the left hand side and changing signs:
tiles
Let's check. If he buys 60 tiles in the first store, he spends:
$0.79×60 + $24 = $47.40 + $24 = $71.40
If he buys 60 tiles in the second store, he spends:
$1.19×60 = $71.40
∴ Darin needs to buy 60 tiles for the cost to be the same at both stores.
In the first store, if Darin bought
In the second store, if Darin bought
For the cost to be the same at both stores, it means (measured in $)
Moving
Let's check. If he buys 60 tiles in the first store, he spends:
$0.79×60 + $24 = $47.40 + $24 = $71.40
If he buys 60 tiles in the second store, he spends:
$1.19×60 = $71.40
∴ Darin needs to buy 60 tiles for the cost to be the same at both stores.
We model the ticket as a rectangle.
For this case what you should know is that the perimeter of the rectangle is given by:
P = 2w + 2l
The area of the rectangle is given by:
A = w * l
In both cases:
w: width
l: long
We have the following system of equations:
32 = 2w + 2l
60 = w * l
Solving the system we obtain:
The dimensions of the ticket are:
(10 cm) * (6 cm)
Answer:
the dimensions of the ticket are:
(10 cm) * (6 cm)
Note: see attached image for system solution
For this case what you should know is that the perimeter of the rectangle is given by:
P = 2w + 2l
The area of the rectangle is given by:
A = w * l
In both cases:
w: width
l: long
We have the following system of equations:
32 = 2w + 2l
60 = w * l
Solving the system we obtain:
The dimensions of the ticket are:
(10 cm) * (6 cm)
Answer:
the dimensions of the ticket are:
(10 cm) * (6 cm)
Note: see attached image for system solution