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4 years ago

Use the relationship between the angles in the figure to answer the question. Which equation can be used to find the value of x?

Mathematics

2 answers:

Anna007 [38]4 years ago

5 0

X=52 i hope i helped

jenyasd209 [6]4 years ago

3 0

Based on your description i think the answer is x=52

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Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

Answer:

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

Solution:

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

4 years ago

Solve −3x+5<17 If someone could do this fast it would really help!

miss Akunina [59]

Answer:

x>-4

Step-by-step explanation:

-3x<12

x>-4

8 0

3 years ago

a football team gained 9 yards on one play and then lost 22 yards on the next. Write a sum of integers to find the overall chang

raketka [301]

$If\ they\ gained\ 9\ yards\ it\ as\ in\ our\ sum\ positive\ number\\\\If\ they\ lost\ 22\ yards\ it\ is\ negative\ number\ in\ our\ sum\\so\\9-22=-13\\\\Their\ overall\ lost\ was\ 13\ yards.\\\\Their\ position\ changed\ by\ 13\ yards\ negatively.(they\ go\ back)$

8 0

4 years ago

Find the area of a rectangle with a length of 4 5/8 inches and a width of 1/2 inch? Is it A. 16/37 in2, B. 37/16 in2, C. 37/2 in

dybincka [34]

Area is length times width. Our length and width are 4 5/8 and 1/2 respectively, so the formula for the area is $A=4 \frac{5}{8}* \frac{1}{2}$ . It will be easier to get that mixed fraction into an improper one and then multiply the fractions straight across the top and straight across the bottom. $A= \frac{37}{8}* \frac{1}{2}$ . Doing that multiplication gives us $A= \frac{37}{16}$ , choice B.

5 0

3 years ago

A projectile is fired straight up from ground level. After t seconds, its height above the ground is s feet, where s= - 16t² + 1

brilliants [131]

For the time period of the projectile at least 192 feet above the ground is between 2 second and 6 second

Since s=128t-16t2, we want to know the 2 times where 128t-16t2=192, as those two values will be the begin and end times of the interval in question. We can rewrite that equation in standard quadratic equation form:

16t2-128t+192=0 or, simplified, 8t2-64t+96=0

or t2-8t+12=0

since it is now in quadratic form, we can solve using the quadratic formula:

t = 2 and 6

So the time period from approximately 2 second and 6 second has the projectile above 192 feet.

Learn more about projectile here:

brainly.com/question/1659208

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4 0

2 years ago