Question

the length of a rectangular yard is 4 feet more than the width. the perimeter of the yard is 208 feet. write the equation that represents the perimeter of the yard. let w represent the width. solve the equation. what are the dimensions of the yard?​

Answer 1

Answer:

Length = 54 ft.

Width = 50 ft.

Step-by-step explanation:

Let the width of the rectangle be 'w'.

According to question ,

Length = w + 4

Perimeter = 208 ft.

We know that $perimeter = 2(l + w)$ where l = length & w = width

So,

$2(w + 4 + w) = 208$

$= > 2(2w + 4) = 208$

$= > 2w + 4 = \frac{208}{2} = 104$

$= > 2w = 104 - 4 = 100$

$= > w = \frac{100}{2} = 50$

Width = 50 ft.

=> Length = 50 + 4 = 54 ft.