Question

What is the slope of a line that is parallel to the line represented by the equation 3x+4y=12?

Answer 1

Slope-intercept form is:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0)

(there is probably another way to do this, but I will be doing it this way)

Isolate the "y" in the equation

3x + 4y = 12       Subtract 3x on both sides

4y = 12 - 3x        Divide 4 on both sides

$y=3-\frac{3}{4}x$  or   $y=-\frac{3}{4} x+3$   The slope is -3/4

For lines to be parallel, they have to have the SAME slope. The given line's slope is -3/4, so the slope of the parallel line is also $-\frac{3}{4}$