Standard form is using only numerical values (numbers.)
Ninety-eight = 98
six-tenth = 0.6
98 + 0.6 = 98.6
98.6 is your answer
Hope this helps
Answer:
Step-by-step explanation:
The total number of lines, n(U) = 18
Let the number of lins with verb be n(V) = 11
Let the number of lines with adjectives be n(A) = 13
n(V n A) = 8
Find the number of lines that have a verb but no adjective, that is, n(V n A')
Mathematically, according to sets theory,
n(V) = n(V n A) + n(V n A')
So,
n(V n A') = n(V) - n(V n A) = 11 - 8 = 3.
Hence, only 3 lines have a verb but no adjectives.
1) (3-x) x (3+x)
2) 5(5-x) x (5+x)
3) (3v-wy) x (3v+wy)
4) 2(k-m) x (k+m) x (k^2+m^2)
5) (ab-4c) x (ab+4c)
Brainliest?
{-8, 0, 8, 16} is the range
Answer:
y=-3/4x-13/2
Step-by-step explanation:
This should be the answer, I am not 100% though
I did y-4=-3/4x(x+14)