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Usimov [2.4K]
3 years ago
13

Balancing the following chemical equation, and determine its reaction type.

Chemistry
1 answer:
Ronch [10]3 years ago
4 0

Answer:

2LiCl +Br_2 \rightarrow 2LiBr +Cl_2

Single displacement reaction.

Explanation:

Hello!

In this case, by firstly rearranging the chemical reaction as shown below:

LiCl +Br_2 \rightarrow LiBr +Cl_2

It is also necessary to balance it at follows:

2LiCl +Br_2 \rightarrow 2LiBr +Cl_2

Thus, since bromine and chlorine are being exchanged as a result of the atoms rearrangement, we infer this is a single displacement reaction.

Best regards!

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A truck is moving at the rate of 40 km/hr. How far does it move when it stops after 5 seconds?
seraphim [82]
First of all, this is the chemistry section, while your question is a physics question. Anyway I'll tell you how to solve it.

First we need to find the rate that the truck moves in a second.

1km = 1000m
40km = 40000m
40000m/hr
1 hour = 60 minutes
40000m/hr ÷ 60 = 666.66(repeating)/minute
1 minute = 60 seconds
666.66m/min ÷ 60 = 11.11(rep)m/s

Next we simply multiply the speed of the truck by the number of seconds it travels.

11.11 × 5 = 55.55
Make sure to round it unless you indicate the repeating decimal.
The truck moved 55.56m in 5 seconds.
6 0
3 years ago
For the reaction at 298 K, 2NO2(g) N2O4(g) the values of ΔH° and ΔS° are -58.03 kJ and -176.6 J/K, respectively. Calculate the v
Ierofanga [76]

Answer:

\Delta G^o=-5.4032 kJ

The temperature for \Delta G^o=0[/tex is [tex]T=328.6 K

Explanation:

The three thermodinamic properties (enthalpy, entropy and Gibbs's energy) are linked in the following formula:

\Delta G^o=\Delta H^o + T*\Delta S^o

Where:

\Delta G^o is Gibbs's energy in kJ

\Delta H^o is the enthalpy in kJ

\Delta S^o is the entropy in kJ/K

T is the temperature in K

Solving:

\Delta G^o=-58.03 kJ - 298K*-0.1766 kJ/K

\Delta G^o=-5.4032 kJ

For \Delta G^o=0:

0=\Delta H^o - T*\Delta S^o

\Delta H^o= T*\Delta S^o

T=\frac{\Delta H^o}{\Delta S^o}

T=\frac{-58.03 kJ}{-0.1766 kJ/K}

T=328.6 K

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<span>Argon and chlorine are both gases at room temperature because they are non-metals.</span>
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They all lose electrons
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