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polet [3.4K]
3 years ago
12

Consider two solutions, solution a and solution

Chemistry
1 answer:
Ronch [10]3 years ago
5 0
Answer is: solution A has 2,57 time greater pH value than solution B.<span>
</span>Concentration of [H⁺] in solution A is than 370x.
pH = -log[H⁺].
pH(solution A) = -log(370x).
pH(solution b) = -log(x).
pH(solution A) / pH(solution B) = -log(370x) / -log(x).
pH(solution A) / pH(solution B) = 2,57.
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Explanation:

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Explanation:

The fractional saturation for hemoglobin can be calculated using the formula

Y_{O_{2} } = \frac{(P_{O_{2} })^{h}  } {(P_{50})^{h}  + (P_{O_{2} })^{h}   }

Where Y_{O_{2} } \\ is the fractional oxygen saturation

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and h is the Hill coefficient

From the question,

{P_{O_{2} } = 40 mm Hg

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Putting these values into the equation, we get

Y_{O_{2} } = \frac{(P_{O_{2} })^{h}  } {(P_{50})^{h}  + (P_{O_{2} })^{h}   }

Y_{O_{2} } = \frac{40^{3} }{22^{3} + 40^{3}  }

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Hence, the fractional saturation for hemoglobin is 0.86.

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3 years ago
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